Answer:
1. P(S) = 373/580
2. P(S|A) = 53/116
3. P(S|Pa) = 481/580
Step-by-step explanation:
Given
---------------------Sale ----- No Sale-----Total
Aggressive ----265 --------315 ----------580
Passive ----------481 ---------99 -----------580
Total --------------746---------414------------1160
A = aggressive approach,
Pa = passive approach,
S = sale,
N= no sale.
(a) Computing P(S)
This is calculated as the division of customers that participated in sales by total customers
Customers that participated in sales = 265 + 481 = 746
Total Customers = 1160
P(S) = 746/1160
P(S) = 373/580
b.
P(S|A) means that the probability that a sales occur given that the aggressive method was used.
To solve this, we check the cell where Sales and Aggressive intersect
The cell element = 265
Total = 580
P(S|A) = 265/580
P(S|A) = 265/580
P(S|A) = 53/116
c.
P(S|Pa) means that the probability that a sales occur given that the passive method was used.
To solve this, we check the cell where Sales and Passive intersect
The cell element = 481
Total = 580
P(S|Pa) = 481/580
The answer is 2/100 or 1/50!
6/10 is equivalent to 60/100.
62/100 - 60/100 = 2/100 = 1/50
So, 6/10 + 1/50 = 62/100
6/10 + 2/100 = 62/100
(Use 1/50 because that’s the simplified answer!)
I hope this made sense! Good luck!
