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charle [14.2K]
3 years ago
5

A computer store bought a program at a cost of ​$10 and sold it at a selling price of ​$13. Find the percent markup.

Mathematics
2 answers:
Contact [7]3 years ago
7 0

Answer:

30%

Step-by-step explanation:

(13-10)/10 × 100% = 3/10 × 100% = 30%

dalvyx [7]3 years ago
4 0
Answer: 30 %

Step-by-step explanation:
Cost = $10
Selling price = $13
Markup = selling price - cost price
= $13 - $10
= $3
percent markup = markup/cost
= $3/$10
= 0.3 = 30%
Percentage markup is 30
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VikaD [51]

Answer:

a) 12:45pm

b) 7:30pm

c) 20 15

d) 00 00

4 0
2 years ago
Two brothers are sharing a certain sum of money in the ratio 2/3 : 3/5, if the largest share was Gh¢500.00. How much was shared
lina2011 [118]

Given:

Two brothers are sharing a certain sum of money in the ratio \dfrac{2}{3}:\dfrac{3}{5}.

The largest share was Gh¢500.00.

To find:

The total amount shared between them.

Solution:

It is given that, two brothers are sharing a certain sum of money in the ratio \dfrac{2}{3}:\dfrac{3}{5}.

First we need to make the denominators common.

Ratio=\dfrac{2\times 5}{3\times 5}:\dfrac{3\times 3}{5\times 3}

Ratio=\dfrac{10}{15}:\dfrac{9}{15}

Ratio=10:9

So, the two brothers are sharing a certain sum of money in the ratio 10:9.

Let the shares of two brothers are 10x and 9x respectively. So, the larger share is 10x.

It is given that the largest share was Gh¢500.00.

10x=500

x=\dfrac{500}{10}

x=50

Now, the total amount shared between them is:

Total=10x+9x

Total=19x

Total=19(50)

Total=950

Therefore, the total amount shared between them is Gh¢950.00.

5 0
3 years ago
5. y = 2x + 6<br> 2x - y=2
Crank

Step-by-step explanation:

y = 2x + 6

2x - y = 2

To solve this system of equations, let's first add the equations together:

(y) + (2x - y) = (2x + 6) + (2)

2x = 2x + 8

2x - 2x = 8

0 = 8

There are no values of x that will make this equation true, so the lines never intersect, and therefore there are no solutions to this system of equations.

5 0
3 years ago
Consider the initial value problem:
Inessa [10]

Answer:

\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2

Step-by-step explanation:

The given initial value problem is;

y''-5y'+6y=-5\sin(2t)---(1)\\y(0)=-5,y'(0)=2

Let

u(t)=y(t)----(2)\\v(t)=y'(t)----(3)

Differentiating both sides of equation (1) with respect to t, we obtain:

u'(t)=y'(t)---(4)\\ \\\implies u'(t)=v(t)---(5)

Differentiating both sides of equation (2) with respect to t gives:

v'(t)=y''(t)----(6)

From equation (1),

y''=5y'-6y-5\sin(2t)\\y''=5v(t)-6u(t)-5\sin(2t)\\\implies v'(t)=5v(t)-6u(t)-5\sin(2t)----(7)

Putting t=0 into equation (2) yields

u(0)=y(0)\\\implies u(0)=-5

Also putting t=0 into equation (3)

u'(0)=y'(0)\\u'(0)=2

The system of first order equations is:

\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2

3 0
3 years ago
What is -3 1/3+5/6 please help me
VLD [36.1K]

Answer:

-15/6

Step-by-step explanation:

-3 1/3+5/6

5/6 - 3 1/3

=> 5/6 - 10/3

=> 5/6 - 20/6

=> -15/6

8 0
2 years ago
Read 2 more answers
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