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ziro4ka [17]
3 years ago
13

Please answer before Friday, May 7

Mathematics
2 answers:
nikitadnepr [17]3 years ago
6 0
The answers are:
definitely true
possibly true
definitely not true
nordsb [41]3 years ago
5 0

Answer:

don't understand, need better explanation than that

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Which of the following is the lowest common denominator for the fractions 5/6 and 3/4? A)4 B)12 C)15 D)24
Ksju [112]
It would be 12 the answer
8 0
3 years ago
Find the smaller of 2 consecutive intergers, x, if the sum of the smaller and 6 times the larger is -29. Write an equation to de
Irina18 [472]

Answer:

x = -5 and x+1( consecutive integer) = -4

obviously x is smaller than the next integer

Step-by-step explanation:

Let the first integer be x

hence the consecutive integer is x +1

according to the give condition

x + 6(x + 1) = -29

x + 6x + 6 = -29

7x = -29 -6

7 x = -35

x = -35/7

x = -5

x + 1 = -5 + 1 = -4

GOOD LUCK FOR THE FUTURE! : )

8 0
3 years ago
Define the set X = {(x,y)|x > 0,y ≤ √x}.
Kitty [74]

The set X is convex.

In geometry, a subset of an affine space over the real numbers, or more broadly a subset of a Euclidean space, is said to be convex if it contains the entire line segment connecting any two points in the subset. A solid cube is an example of a convex set, whereas anything hollow or with an indent, such as a crescent shape, is not. Alternatively, a convex region is a subset that crosses every line into a single line segment.

b)The set X is convex as any two points on the set X is included in the whole set as x>0. So a line joining any two points on the set X is completely inside the set x.

c)set X is not a closed set as the compliment of the set is not an open set.

d)Set X is not bounded. If a set S contains both upper and lower bounds, it is said to be bounded. A set of real numbers is therefore said to be bounded if it fits inside a defined range. hence set x is not bounded.

To learn more about convex sets:

brainly.com/question/12577430

#SPJ9

3 0
1 year ago
It is known that the population variance equals 484. With a .95 probability, the sample size that needs to be taken if the desir
Ksju [112]

Answer:

We need a sample size of at least 75.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, we find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

The standard deviation is the square root of the variance. So:

\sigma = \sqrt{484} = 22

With a .95 probability, the sample size that needs to be taken if the desired margin of error is 5 or less is

We need a sample size of at least n, in which n is found when M = 5. So

M = z*\frac{\sigma}{\sqrt{n}}

5 = 1.96*\frac{22}{\sqrt{n}}

5\sqrt{n} = 43.12

\sqrt{n} = \frac{43.12}{5}

\sqrt{n} = 8.624

(\sqrt{n})^{2} = (8.624)^{2}

n = 74.4

We need a sample size of at least 75.

6 0
3 years ago
Read 2 more answers
This is almost the last one
Kamila [148]
The answer is 4 because the portion labelled J shows a constant function but is not at the starting point
5 0
3 years ago
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