The equation in slope-intercept form represents a line that is parallel to y = 12x − 2 and passes through the point (−8,1) is y = 12x + 97
<em><u>Solution:</u></em>
Given that we have to write the equation in slope intercept form for line that is parallel to y = 12x − 2 and passes through the point (−8, 1)
<em><u>The slope intercept form is given as:</u></em>
y = mx + c ---- eqn 1
Where "m" is the slope of line and "c" is the y - intercept
Given equation of line is y = 12x - 2
On comparing the above equation with eqn 1,
m = 12
Thus slope of line is 12
We know that slopes of parallel lines are equal
Therefore, slope of line parallel to given line is also 12
Given point is (-8, 1)
We have to find the equation of line passing through (-8, 1) with slope m = 12
Substitute m = 12 and (x, y) = (-8, 1) in eqn 1
1 = 12(-8) + c
1 = -96 + c
c = 97
Substitute c = 97 and m = 12 in eqn 1
y = 12x + 97
Thus the required equation of line is found
Answer:
2.5
Step-by-step explanation:
The formula to find the midpoint of a line segment: 
<u><em>Where:</em></u>

1) Substitute the values into the midpoint formula.

2) Solve it.
= 
= (2.5, 8.5)
Hey,
If you meant that

than

![= \sqrt[4]{111^{5}}](https://tex.z-dn.net/?f=%3D%20%20%5Csqrt%5B4%5D%7B111%5E%7B5%7D%7D%20%20)
but you can't find the exact number.
Hope this helps :) and don't forget to choose the brainliest please :)
Answer:
The roots of the equation are x=-3 and x=-2.5
Step-by-step explanation:
<u><em>The correct quadratic equation is</em></u>
2x^2+11x+15=0
we know that
The formula to solve a quadratic equation of the form
is equal to
in this problem we have
so
substitute in the formula
therefore
The roots of the equation are x=-3 and x=-2.5
Answer:
its 69 i think
Step-by-step explanation: