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Luba_88 [7]
3 years ago
13

on average, the U.S. produces 36.5 millions tons of fruit each year. about how much fruit does it produce in 2.25 years ?

Mathematics
2 answers:
Eduardwww [97]3 years ago
4 0

Answer:

In 2.25 years the U.S, will produce 82125000 tons of fruit

Step-by-step explanation:

Ratio:

36.5 million tons : 1 year

<em>f</em> tons : 2.25 years

Since 2.25 ÷ 1 = 2.25, we need to multiply 36.5 million by 2.25

36.5 million = 36500000

36500000 · 2.25 = 82125000

<em>f </em>= 82125000

Karo-lina-s [1.5K]3 years ago
3 0
I usually break it down so 2.25 is 2 1/4 so then a 36.5 million is basically 36m 1/2 36+36 is 72+1 is 73 and a 1/4 of 36 is 9 and that's it just right your answer put using the info here and it should be right if not pls let me know so I can figure out what I did wrong and try again
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The ratio of the number of cups of yellow paint to the number of cups of blue paint that Greg mixed to make a shade of green pai
ziro4ka [17]

Answer:

Part A:  A ratio of 2:1  means that he uses<u><em> </em></u><u><em>2 cups of yellow paint for each cup of blue paint.</em></u>

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Part B: The ratio of yellow to blue is 2:1 = 2/1. So, if for 2 yellow is 1 blue, then for 1 yellow is x:

2/1 = 1/x

x = (1*1) / 2

x = 1/2

<u><em>For each cup of yellow paint, Greg should add 1/2 cup of blue paint.</em></u>

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 Part C: 6 cups cost $54, then 1 cup cost:

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7 0
3 years ago
Find the work required to move an object in the force field F = ex+y &lt;1,1,z&gt; along the straight line from A(0,0,0) to B(-1
storchak [24]

Answer:

Work = e+24

F is not conservative.

Step-by-step explanation:

To find the work required to move an object in the force field  

\large F(x,y,z)=(e^{x+y},e^{x+y},ze^{x+y})

along the straight line from A(0,0,0) to B(-1,2,-5), we have to parameterize this segment.

Given two points P, Q in any euclidean space, you can always parameterize the segment of line that goes from P to Q with

r(t) = tQ + (1-t)P with 0 ≤ t ≤ 1

so  

r(t) = t(-1,2,-5) + (1-t)(0,0,0) = (-t, 2t, -5t)  with 0≤ t ≤ 1

is a parameterization of the segment.

the work W required to move an object in the force field F along the straight line from A to B is the line integral

\large W=\int_{C}Fdr

where C is the segment that goes from A to B.

\large \int_{C}Fdr =\int_{0}^{1}F(r(t))\circ r'(t)dt=\int_{0}^{1}F(-t,2t,-5t)\circ (-1,2,-5)dt=\\\\=\int_{0}^{1}(e^t,e^t,-5te^t)\circ (-1,2,-5)dt=\int_{0}^{1}(-e^t+2e^t+25te^t)dt=\\\\\int_{0}^{1}e^tdt-25\int_{0}^{1}te^tdt=(e-1)+25\int_{0}^{1}te^tdt

Integrating by parts the last integral:

\large \int_{0}^{1}te^tdt=e-\int_{0}^{1}e^tdt=e-(e-1)=1

and  

\large \boxed{W=\int_{C}Fdr=e+24}

To show that F is not conservative, we could find another path D from A to B such that the work to move the particle from A to B along D is different to e+24

Now, let D be the path consisting on the segment that goes from A to (1,0,0) and then the segment from (1,0,0) to B.

The segment that goes from A to (1,0,0) can be parameterized as  

r(t) = (t,0,0) with 0≤ t ≤ 1

so the work required to move the particle from A to (1,0,0) is

\large \int_{0}^{1}(e^t,e^t,0)\circ (1,0,0)dt =\int_{0}^{1}e^tdt=e-1

The segment that goes from (1,0,0) to B can be parameterized as  

r(t) = (1-2t,2t,-5t) with 0≤ t ≤ 1

so the work required to move the particle from (1,0,0) to B is

\large \int_{0}^{1}(e,e,-5et)\circ (-2,2,-5)dt =25e\int_{0}^{1}tdt=\frac{25e}{2}

Hence, the work required to move the particle from A to B along D is

 

e - 1 + (25e)/2 = (27e)/2 -1

since this result differs from e+24, the force field F is not conservative.

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