Find the zeros from the factored form Quadratic Equation y=-x(x-3) ( ,0) & ( ,0)
1 answer:
Answer:
(0, 0) and (3, 0)
Step-by-step explanation:
Zeros of any equation means, value of variable x at y = 0.
Given quadratic equation is,
y = -x(x - 3)
For y = 0,
-x(x - 3) = 0
x = 0
And (x - 3) = 0
x = 3
Therefore, x-intercepts of the given quadratic equation will be,
x = 0, 3
Points showing the x-intercepts will be,
(0, 0) and (3, 0)
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- Acute: less than 90 degrees
- Right: equal to 90 degrees
- Obtuse: greater than 90 degrees
- Straight: equal to 180 degrees
4. m∠LGH = 14 ---acute
5. m∠SRT = 114 ---obtuse
6. m∠SLI = 90 ---right
7. m∠1 = 139 ---obtuse
8. m∠L = 179 ---obtuse
m∠P = 73 ---acute
Answer:
d
Step-by-step explanation:
For Y=2x+10 X=y/2 -5. Second x/3
C=2*3.14*7.6
C=47.728
Round.
47.7
Therefore, the circumference is 47.7 m.
(72/80)x90=81
Divide seventy-two by eight and multiply it Ninety.
