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Answer:
- The function f(x) = 9,000(0.95)^x represents the situation.
- After 2 years, the farmer can estimate that there will be about 8,120 bees remaining.
- The range values, in the context of the situation, are limited to whole number
Step-by-step explanation:
The "growth" rate is -5%, so the growth factor, the base in the exponential equation, is 1.00-5% =0.95.
Using x=2, we find the population in 2 years is expected to be about ...
f(2) = 9000·0.95^2 ≈ 8123 . . . . about 8120
Using x=4, we find the population in 4 years is expected to be about ...
f(4) = 9000·0.95^4 ≈ 7331 . . . . about 7330
Since population is whole numbers of bees, the range of the function is limited to whole numbers.
The domain of the function is numbers of years. Years can be divided into fractions as small as you want, so the domain is not limited to whole numbers.
The choices listed above are applicable to the situation described.
Answer:
A: W = 8x
B: 12y + 320
C: 44
Step-by-step explanation:
A: Lana can make $8 an hour.
W = 8x
B: She makes $12 per hour for every hour of overtime. This means that she already worked 40 hours with regular pay. She has already made $320.
40 × $8 = $320
S = 12y + 320
C: Plug in the amount Lana earned into the second equation. The second equation will account for pay from both regular and overtime hours.
S = 12y + 320
368 = 12y + 320
368 - 320 = (12y + 320) - 320
48 = 12y
48/12 = (12y)/12
4 = y
y = 4
Lana worked 4 hours of overtime and 40 hours of regular hours. In total, she worked 44 hours.
4 + 40 = 44
6lbs divided by 4, x 16 = 24oz is your answer
Answer:
Step-by-step explanation:
When dividing 46 by 9 quotient is 5 and remainder is 46 - 45 = 1
