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3 years ago

X^4=15 is an exponential equation?

Mathematics

1 answer:

miskamm [114]3 years ago

8 0

Answer:

No. It is not an Exponential Equation.

Step-by-step explanation:

Given $x^{4} =15$

By the Definition of Exponential Equation which states.

"The equation is said to be an exponential equation when it has a variable occurred in the exponent and which have the same base."

For Example:

All given below are said to be exponential equations.

$5^{x} =5^{2} \\7^{x}=49\\$

which can be rewritten as

$7^{x}=7^{2}$

Now in the given equation $x^{4}=15$ it doesn't have same base neither any means the base can be made same,hence the given equation is not an exponential equation

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Paint is sold in a cylindrical container with a radius of 4 inches and a height of 10 inches. If the paint costs $0.05 per cubic

galina1969 [7]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

write a function g whose graph represents a translation 2 units to the right followed by a horizontal stretch by a factor or 2 o

Alenkinab [10]

$\bf f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}\\\\
f(x)=&{{ A}} \left|{{ B }}x+{{ C}} \right|+{{ D}}
\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see,

$\bf f(x)=|x| \implies \begin{array}{lllccll}
f(x)=&1|&1x&+0|&+0\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}$

so, to shift it to the right by 2 units, simply set C = 2.
to stretch it by 2, set A = 1/2.

the smaller A is, the wider it opens, the larger it is, the more it shrinks.

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3 years ago

Problems

svlad2 [7]

Answer:

Step-by-step explanation:

3 caterpillars double every minute (3×2=6). after 4 minutes (6×4=24). He captured 7 caterpillars within the four minutes (24-7=17).

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3 years ago

How to find slope within two sets of points

EastWind [94]

The slope within two sets of points is calculated using the slope equation $m = \frac{y_2 -y_1}{x_2 -x_1}$

<h3>What is slope?</h3>

The slope of a line or points is the rate of change of the line.

This in other words means that, the vertical change per unit horizontal change

Assume that the points are given as:

(x1, y1) and (x2, y2)

The slope (m) of the points is:

$m = \frac{y_2 -y_1}{x_2 -x_1}$

Hence, the equation of two sets of points is $m = \frac{y_2 -y_1}{x_2 -x_1}$