Answer:
(2,-4)
Step-by-step explanation:
when reflecting across the Y-axis from quadrant 3 to quadrant 4, a sign change from (-,-) to (+,-) would occur.
Remember that c is the initial height. Since we the rocket is in a 99-foot cliff, c=99. Also, we know that the velocity of the rocket is 122 ft/s; therefore v=122
Lets replace the values into the the vertical motion formula to get:

Notice that the rocket hits the ground at the bottom of the cliff, which means that the final height is 99-foot bellow its original position; therefore, our final height will be h=-99
Lets replace this into our equation to get:


Now we can apply the quadratic formula

where a=-16, b=122, and c=198


or


or


or

Since the time can't be negative, we can conclude that the rocket hits the ground after 9 seconds.
Answer: D. 7
Step-by-step explanation:
The problem tells you that x = 0 so replace everything that is x in the equation with 0 so the problem becomes
7 + (-3(0)^2)
Now we just solve the problem normally.
solve the problem in the parenthesis first, we must multiply -3 times 0^2 is 0
so now our problem is 7 + 0 which is 7