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antoniya [11.8K]

3 years ago

14

Look at the corresponding pairs of numbers on the top and bottom number lines. Write a multiplication sentence to show how 10 ga

llons and 300 miles are related. How are 5 gallons and 150 related? How are 1 gallon and 30 miles related?

2 answers:

nata0808 [166]3 years ago

5 0

Answer:

1 gallon = 30 milles

×5

=5 gallon = 150 milles

×10

=10 gallon =300 milles

Step-by-step explanation:

1 gallon = 30 milles

×5

=5 gallon = 150 milles

×10

=10 gallon =300 milles

garik1379 [7]3 years ago

4 0

1 gallon = 30 milles

×5

=5 gallon = 150 milles

×10

=10 gallon =300 milles

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Find the discriminant of the following equation.<br> 4x2 + 16x + 16 = 0 ...?

kenny6666 [7]

Discriminant = b^2 - 4ac

a = 4

b = 16

c = 16

16^2 - 4(4 x 16)

256 - (4x64)

256 - 256 = 0

Therefore it only has one root

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3 years ago

What equations are equivalent to1/4(8x+56)=20

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Answer:

Step-by-step explanation:

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2 years ago

FIFTY POINTS!! Please help! I'll give brainliest

melomori [17]

Answer:

4851 ways

Step-by-step explanation:

The fish have 3 choices. They can make it above, below, or though the pipe. Keep in mind there are 100 fish total:

group 1 + group 2 + group 3 = 100

If we keep group 3 (the fish that swim below the pipe) constant, say 1, and increment the other two (group 2 starting off at 1) we find 98 possibilities.

98 + 1 + 1 = 100,

97 + 2 + 1 = 100,

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If we continue this pattern, we have 98 + 97 + 96... + 1 total possibilities to partition this school of fish.

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3 years ago

Students have organized

Olenka [21]

Answer:

Part A. At least 6 hours

Part B. In less than 2.5 hours Elijah will be behind Mercedes

Part C. In more than 2.5 hours Elijah will be ahead Aubrey

Step-by-step explanation:

D = distance

v =speed

t = time

Formula connecting D, v and t:

$D=v\cdot t$

Part A.

Steve's speed: $v=3.5\ mph$

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$3.5\cdot t\ge 21\\ \\35t\ge 210\ [\text{Multiplied by 10}]\\ \\t\ge \dfrac{210}{35}\\ \\t\ge \dfrac{30}{5}\\ \\t\ge 6$

It would take Steve at least 6 hours to walk at least 21 mi on Day 1.

Part B.

Mercedes's speed: $v_M=2.4\ mph$

Elijan's speed: $v_E=3.2\ mph$

Elijan's Distance walked: $D_E$ miles

Mercedes's Distance walked: $D_M$ miles

Time: x hours

Mercedes is 2 miles ahead, so

$D_E=3.2x\\ \\D_M=2.4x+2$

Elijan will be behind when

$D_E$

In 2.5 hours Elijan will catch up Mercedes, and in less than 2.5 hours Elijah will be behind Mercedes.

Part C.

Aubrey's speed: $v_M=3\ mph$

Elijan's speed: $v_E=3.2\ mph$

Elijan's Distance walked: $D_E$ miles

Aubrey's Distance walked: $D_A$ miles

Time: x hours

At the beginning of Day 3, Elijah starts walking at the marker for Mile 42, and Aubrey starts walking at the marker for Mile 42.5.

$D_E=42+3.2x\\ \\D_A=42.5+3x$

Elijan will be ahead of Aubrey when

$D_E>D_A\\ \\42+3.2x> 42.5+3x\\ \\3.2x-3x>42.5-42\\ \\0.2x>0.5\\ \\2x>5\ [\text{Multiplied by 10}]\\ \\x>\dfrac{5}{2}\\ \\x>2.5\ hours$

In 2.5 hours Elijan will catch up Aubrey, and in more than 2.5 hours Elijah will be ahead Aubrey.

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Harrizon [31]

Double
from initial amont of P to final amount of 2P
so

2P=P(1.071)^time
divide both sides by P
2=1.071^time
take the ln of both sides
ln2=timeln1.071
divide both sides by ln 1.071
(ln2)/(ln1.071)=time needed
using calculator
10.1052=time needed
about 10.1 hours

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3 years ago