2x+7 <= 3x-5
subtract 2x from each side
7 <= x-5
add 5 to each side
12 <= x
x must be greater than or equal to 12
12 18 24 and 107 are possible solutions
Answer:
x=5.333
y=3
Step-by-step explanation:
given, y=5-2............(1)
1-3x+y=-12...............(2)
y=5-2=3
put y=3 in equ (2)
1-3x+3=-12
1+3+12=3x
3x=16
x=
x=5.333
hence, x=5.333
y=3 answer
Answer:
Displacement = 0 mi
Distance = 164,996.45 mi
Step-by-step explanation:
In this case, the displacement will be zero because the satellite goes back to its starting point after one day. If there is no distance traveled between the starting point and the ending point, then the Displacement will be zero.
When it comes to the distance, we will need to calculate the perimeter of the circle the satellite describes when making one whole turn around the earth.
The perimeter of a circle is given by the equation:

so we need to start by finding what the radius of the circle is. This radius if found by adding the radius of the earth and the distance above the equation the satellite is located at, so we get that:

where h is the height of the satellite, so the radius of the circle is:

so
r=26,260 mi
so now we can use the perimeter equation to get:


So the distance traveled by the satellite in one day will be:
P=164,996.45 mi.
Answer:
10
Step-by-step explanation:
The expansion of this is 10x+15. So, the coefficient of x is 10 in this equation.
Sin 28 = 3/AB
AB= 3/ sin 28
AB=6.4