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Oxana [17]
3 years ago
7

Graph a point. Start at your origin, move left 10 units, and then move up three units which ordered pair is the point you graphe

d
Mathematics
2 answers:
aliya0001 [1]3 years ago
8 0

Answer:

(-10,3)

Step-by-step explanation:


disa [49]3 years ago
5 0
(-10,3) That is your answer
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s2008m [1.1K]
The students on the right hand side had better overall results

There were less people on the left hand side of the room this affects the average even with the right hand side having two zeros, another thing which the left hand side didn’t have.

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2 years ago
Are the graphs of the lines in the pair parallel? Explain. y=2\3x-17 4x-6y=-7
Papessa [141]
<span>y=2\3x-17and  4x-6y=-7 implies  - 6y= - 4x -7, and then y= (-4/-6)x +7/6 and so 
y=2/3x+7/6

but when we have y=ax+b and y=a'x+b', the two lines are parallels if a=a', in our case 2/3=2/3 the lines are parallel
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6 0
3 years ago
To rationalize the denominator of 2/square 13+ squared 11 , you should multiply the expression by which fraction?
eimsori [14]

<u><em>Answer:</em></u>

You should multiply the expression by \frac{\sqrt{13}-\sqrt{11}}{\sqrt{13}-\sqrt{11}}

<u><em>Explanation:</em></u>

To rationalize any expression, you must multiply it by its conjugate. A conjugate is defined as a similar expression to the original one but with an opposite sign

<u>This means that:</u>

The conjugate of a + b would be a -  b

Now, the given expression is \frac{2}{\sqrt{13}+\sqrt{11}}

<u>Consider the denominator:</u>

From the above, we can conclude that the conjugate of \sqrt{13}+\sqrt{11} is \sqrt{13}-\sqrt{11}

<u>And, remember that</u> we need to keep the value of the expression unchanged. This means that we must multiply both the numerator and the denominator by the same value

<u>Therefore:</u>

You should multiply the expression by \frac{\sqrt{13}-\sqrt{11}}{\sqrt{13}-\sqrt{11}} in order to rationalize the denominator

Hope this helps :)

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