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Vika [28.1K]
3 years ago
5

Plz help!

Mathematics
2 answers:
kow [346]3 years ago
6 0

Answer:

A- the slope is 2/3 and the y-intercept is -2

Step-by-step explanation:

We can find the slope using this formula- y=mx+b

so, for this it looks like the y-intercept(<em>the part of the line on the y-axis)</em> is -2

The slop can be found by picking two points, in this case I will pick

(0,-2)(x1,y1) and (3,0)(x2,y2)

Now, you can divide<em> </em>\frac{y2-y1}{x2-x1}

so, it would be 0-(-2)/3-0= 2/3

So your slope is 2/3 and your y-intercept is -2

Nataly [62]3 years ago
5 0
A- the slope is 2/3 and the y-intercept is -2
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GenaCL600 [577]

Answer:

a) La fuerza neta que experimenta un ascensor cuando asciende con una aceleración de 4 metros por segundo al cuadrado es 600 newtons hacia arriba.

b) La fuerza neta que experimenta un ascensor cuando desciende con una aceleración de 6 metros por segundo al cuadrado es 900 newtons hacia abajo.

c) Por la fuerza de tensión sobre el cable del ascensor.

Step-by-step explanation:

a) La fuerza neta experimentada por el ascensor (F), en newtons, es:

F = m\cdot a (1)

Donde:

m - Masa, en kilogramos.

a - Aceleración, en metros por segundo cuadrado.

Si sabemos que m = 150\,kg y a = 4\,\frac{m}{s^{2}}, entonces la fuerza neta del ascensor es:

F = m\cdot a

F = 600\,N

La fuerza neta que experimenta un ascensor cuando asciende con una aceleración de 4 metros por segundo al cuadrado es 600 newtons hacia arriba.

b) Si sabemos que m = 150\,kg y a = -6\,\frac{m}{s^{2}}, entonces la fuerza neta del ascensor es:

F = m\cdot a

F = -900\,N

La fuerza neta que experimenta un ascensor cuando desciende con una aceleración de 6 metros por segundo al cuadrado es 900 newtons hacia abajo.

c) De manera simplificada, el ascensor experimenta dos fuerzas que definen la fuerza y aceleración netas: (i) La fuerza de tensión sobre el cable que traslada el ascensor y el peso total del ascensor, opuesta a la anterior y en función de la aceleración gravitacional. Puesto que la masa no varía en ningún caso, se concluye que el peso es constante, entonces la diferencia de valores se debe a la fuerza por tensión del cable. En el descenso, es fuerza es menor que en el ascenso.

8 0
3 years ago
∣∣x+34∣∣=−11, How do you solve this
VMariaS [17]

Answer:

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Step-by-step explanation:

Since this is absolute value, we know the answer has to be positive, because distance has to be positive. We see it is negative, and that cannot be, so the answer is no solutions.

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3 years ago
What is the area of a rectangle that is 3.1 cm wide and 4.4 cm long? Enter the full-precision answer first to see the correspond
Brrunno [24]

Answer:  Without rounding : 13.64 (square cm)

Rounded answer : 13.6(square cm)

Step-by-step explanation:

We know that the area of a rectangle is given by :-

A=l\times w, where l is the length and w is the width of the rectangle.

Given : The dimensions of a rectangle are 3.1 cm wide and 4.4 cm long.

Then, the area of rectangle will be:-

A=4.4\times 3.1=\dfrac{44}{10}\times\dfrac{31}{10}\\\\=\dfrac{1364}{100}=13.64\text{ cm}^2\approx13.6\ cm^2  \text{Rounded to the nearest tenth}

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The rectangular classroom is 36ft in length and 32 feet in with. The scale drawing of the floor has a length of 9 inches. What i
Flauer [41]

Answer:

72 inch²

Step-by-step explanation:

Rectangular classroom

Length=36ft

Width=32ft

scale drawing length = 9 inches

Scale drawing width=x

Ratio of the length to the scale drawing length = 36/9

Ratio of the width to the scale drawing width=32/x

To find x

36/9=32/x

Cross product

36x=32*9

x=288/36

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x=8

Area of a rectangle= length × width

Length=9 inches

Width=8 inches

Area of the rectangular classroom= 9 inches × 8 inches

=72 inch²

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