Answer:
its about checkers cou nt and answer
Step-by-step explanation:
Answer:
<h2>x = 10√3</h2>
<u>Step-by-step explanation:</u>
cos 45° = base / hypotenuse
1/√2 = base / 15√2
15√2 = base√2
Base, = 15
sin 60° = perpendicular / hypotenuse
hypotenuse = x
√3/2 = 15 / x
x √3 = 30
x = 30 / √3
x = 10√3
Answer:
d=10u
Q(5/3,5/3,-19/3)
Step-by-step explanation:
The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane
, then r will have the next parametric equations:

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

Substitute the value of
in the parametric equations:

Those values are the coordinates of Q
Q(5/3,5/3,-19/3)
The distance from Po to the plane

-2 or -2/1 because the ratio is y over x and the line is going down 2 (-2) every time it goes to the right once (1)
Answer:
we dont have a question or picture..?