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uysha [10]
2 years ago
13

What is the greatest common factor of the number pair 6x and 9x

Mathematics
1 answer:
Ulleksa [173]2 years ago
4 0

Answer:

gcf is 3x. pls mark brainliest

Step-by-step explanation:

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Graphing required <br><br><br><br> answer ASAP
raketka [301]
This the answer l guess

5 0
3 years ago
Change the unit of capacity 12 c = qt
sattari [20]

Answer:

Step-by-step explanation:

Comment

There are 4 cups in a quart.

There are 12 cups in x quarts.

Solution

4/12 = 1 / x                               Cross multiply

4x = 12*1                                  Combine

4x = 12                                     Divide both sides by 4

4x/4 = 12/4

x = 3 quarts

Answer

3 quarts.

3 0
2 years ago
Read 2 more answers
Zachary has been trying to work on an essay for almost three hours, but he can't seem to focus for more than 15 or 20 minutes at
malfutka [58]
He should take breaks every 15 minutes and he should also eat a healthy snack and drink lots of water
4 0
3 years ago
Use the diagram to complete the statement. Triangle J K L is shown. Angle K J L is a right angle. Angle J K L is 52 degrees and
zzz [600]

Answer:

\bold{sin(38^\circ)=cos(52^\circ)}

Step-by-step explanation:

Given that \triangle KJL is a right angled triangle.

\angle JKL = 52^\circ\\\angle KLJ = 38^\circ

and

\angle KJL = 90^\circ

Kindly refer to the attached image of \triangle KJL in which all the given angles are shown.

To find:

sin(38°) = ?

a) cos(38°)

b) cos(52°)

c) tan(38°)

d) tan(52°)

Solution:

Let us use the trigonometric identities in the given \triangle KJL.

We have to find the value of sin(38°).

We know that sine trigonometric identity is given as:

sin\theta =\dfrac{Perpendicular}{Hypotenuse}

sin(\angle JLK) = \dfrac{JK}{KL}\\OR\\sin(38^\circ) = \dfrac{JK}{KL}....... (1)

Now, let us find out the values of trigonometric functions given in options one by one:

cos\theta =\dfrac{Base}{Hypotenuse}

cos(\angle JLK) = \dfrac{JL}{KL}\\OR\\cos(38^\circ) = \dfrac{JL}{KL}....... (2)

By (1) and (2):

sin(38°) \neq cos(38°).

cos(\angle JKL) = \dfrac{JK}{KL}\\OR\\cos(52^\circ) = \dfrac{JK}{KL} ...... (3)

Comparing equations (1) and (3):

we get the both are same.

\therefore \bold{sin(38^\circ)=cos(52^\circ)}

6 0
3 years ago
Plz help me due today help me
vekshin1

Answer:

7.7 %

Step-by-step explanation:

352-325

=27

27/352 x 100/1

7.670

=7.7%

6 0
3 years ago
Read 2 more answers
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