2 years ago

What is the answer?! PLEASE HELP ME WITH THIS QUESTION

1 answer:

5 0

I’m pretty you would have to pay $5.03 for two extra panes because if you do $13.25 divided by 5 it will equal 2.65 which is the unit price for it and if you do 2.65 times two you would get 5.3

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Show that a sequence {sn} coverages to a limit L if and only if the sequence {sn-L} coverages to zero.

Andreyy89

Let ${s_n}_{n\in\Bbb N}$ be a sequence that converges to $L$ . This means for any $\varepsilon>0$ , there is some $N$ such that $|s_n-L|$ for all $n>N$ . From this inequality we see that $|(s_n-L)-0|$ , so it follows that $s_n-L\to0$ .

On the other hand, let ${s_n-L}$ be a sequence that converges to 0. This means $|(s_n-L)-0|$ for all large enough $n$ , and we get the simpler inequality for free, $|s_n-L|$ , so it follows that $s_n\to L$ .