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2 years ago

Change the unit of capacity 12 c = qt

Mathematics

2 answers:

Firdavs [7]2 years ago

4 0

The Answer would be 3 quarts

sattari [20]2 years ago

3 0

Answer:

Step-by-step explanation:

Comment

There are 4 cups in a quart.

There are 12 cups in x quarts.

Solution

4/12 = 1 / x Cross multiply

4x = 12*1 Combine

4x = 12 Divide both sides by 4

4x/4 = 12/4

x = 3 quarts

Answer

3 quarts.

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Please answer soon I need this answer very quickly for math. Thank you!

Kazeer [188]

a. First five terms: 9,13,17,21,25

b. Sum of first 25 terms = 1425

c. The given sequence is an arithmetic sequence because the common difference between two consecutive terms is same.

Further explanation:

Given

Formula of sequence

$a_n=4n+5$

1. First 5 terms:

For first 5 terms, we have to put n=1,2,...5,

So,

$For\ n=1\\a_1=4(1)+5\\=4+5\\=9\\For\ n=2\\a_2=4(2)+5\\=8+5\\=13\\For n=3\\a_3=4(3)+5\\=12+5\\=17\\For\ n=4\\a_4= 4(4)+5\\=16+5\\=21\\For\ n=5\\a_5=4(5)+5\\=20+5\\=25\\First\ 5\ terms\ are: 9,13,17,21,25$

2. Sum of first 25 terms:

For that we have to find 25th term first

$a_{25} = 4(25)+5\\=100+5\\=105$

The formula for sum is:

$S_n=\frac{n}{2}(a_1+a_n)}\\Putting\ the\ values\\S_n=\frac{25}{2}(9+105)\\=12.5(114)\\=1425$

3. Type of sequence

The given sequence is an arithmetic sequence because the common difference between two consecutive terms is same.

i.e.

$d=4$

Keywords: Arithmetic sequence, Sum of arithmetic sequence

Learn more about arithmetic sequence at:

#LearnwithBrainly

4 0

3 years ago

Deluxe River Cruises operates a fleet of river vessels. The fleet has two types of vessels: A type-A vessel has 60 deluxe cabins

bixtya [17]

Answer: It should be used 2 for type-A and 3 for type-B to minimize the cost.

Step-by-step explanation: As it is stipulated, x relates to type-A and y to type-B.

Type-A has 60 deluxe cabins and B has 80. It is needed a minimum of 360 deluxe cabins, so:

60x + 80y ≤ 360

For the standard cabin, there are in A 160 and in B 120. The need is for 680, so:

160x + 120y ≤ 680

To calculate how many of each type you need:

60x + 80y ≤ 360

160x + 120y ≤ 680

Isolating x from the first equation:

x = $\frac{360 - 80y}{60}$

Substituing x into the second equation:

160( $\frac{360 - 80y}{60}$ ) + 120y = 680

-3200y+1800y = 10200 - 14400

1400y = 4200

y = 3

With y, find x:

x = $\frac{360 - 80y}{60}$

x = $\frac{360 - 80.3}{60}$

x = 2

To determine the cost:

cost = 42,000x + 51,000y

cost = 42000.2 + 51000.3

cost = 161400

To keep it in a minimun cost, it is needed 2 vessels of Type-A and 3 vessels of Type-B, to a cost of $161400

8 0

3 years ago

The sides of a quadrilateral whose sides are 85cm 143cm 165cm and 85cm and one of the diagonals is 154cm

yaroslaw [1]

Answer:85cm is kept comstant for a while

Step-by-step explanation:

For 2nd part

1m 80 cm

=1×100cm+ 80 cm

=100cm+ 80 cm

=180cm

#According to question,

If both are added then,

=85cm+180 cm

=265cm

please brainlest

Step-by-step explanation:

7 0

3 years ago

What is the answer to this math problem 40+40x0+1=

Anna71 [15]

PEMDAS is
Parenthesis
Exponets
Multiply
Divide
Add
Subtract
therefore, you would do 40*0=0+40+1=41

5 0

3 years ago

A merchant mixed 15 Ib of a cinnamon tea with 10 Ib of spice tea. The 25-pound mixture sells for $65. A second mixture included

sertanlavr [38]

Answer:

Step-by-step explanation:

12 x + 4 y = 42 .............1

16 x + 8 y = 64 .............2

Eliminate y

multiply (1)by -2

Multiply (2) by 1

-24 x -8 y = -84

16 x 8 y = 64

Add the two equations

-8 x = -20

8 0

3 years ago

Read 2 more answers