Question

• PQ²+PR²=QR²• PQ²+QR²=PR²• PR²- PQ²=QR²• PR²- QR²=PQ²​

Answer 1

Answer:

Option A

${pq}^{2} + {pr}^{2} = {qr}^{2}$

Step-by-step explanation:

This is because here,

PQ is the Height of the right triangle.

QR is the Base of the right triangle.

PR is the Hypotenuse of the right triangle.

So, as according to Pythagoras Theorem,

${base}^{2} + {height}^{2} = {hypotenuse}^{2}$

Also,

${pq}^{2} + {qr}^{2} = {pr}^{2}$

Not,

${pq}^{2} + {pr}^{2} = {qr}^{2}$

Hence, Option A is not correct.