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Stella [2.4K]
3 years ago
13

How many solutions does the given system of equations have?

Mathematics
1 answer:
svetoff [14.1K]3 years ago
8 0

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What is the area of the following polygon? Explain your process for how you arrived at the final area. Show your work
Reptile [31]
46 because 14+13=46 and cm
7 0
2 years ago
Grace and her brother need $400 to go to band camp. Their parents have agreed to help them earn money by paying them $25 each ti
soldi70 [24.7K]

Answer:

25m + 10b = 400

Step-by-step explanation:

Total amount that can be earned = $ 400

Amount earned on mowing a lawn = $ 25

Amount earned per hour on babysitting = $10

Amount earned for mowing one lawn is $ 25, so amount earned for mowing m lawns will be $ 25m

Amount earned for one hour of babysitting is $ 10, so amount earned for babysitting for b hours will be $ 10b

Total amount earned = Amount earned from mowing m lawns + Amount earned from babysitting for b hours

Using the values from above, we can set up the equation as:

400 = 25m + 10b

7 0
3 years ago
Find the gradients for line A and B.<br><br> See pic attached
pogonyaev
Gradient is the difference between the y-axis and the x-axis
Gradient = y2-y1/x2-x1
Choose any two point making a triangle
Line B (0,8) (4,0)
This makes a triangle please go look at the graph once again! The the triangle should not have half squares but full!
Line A (5,14)(2,2)
Now plug in the variable
The difference between the Y and X
Line B 0-8/4-0
Line B gradient =-2
Line A 2-14/2-5
Line A gradient = +4

Finalized answer
Line B gradient = -2
Line A gradient = +4
8 0
2 years ago
The entry ticket to a local museum costs $12 for an adult and $8 for a child. A group of 100 people paid an entry fee of $1,056.
Vitek1552 [10]
Answer is 64 adults and 36 children
4 0
2 years ago
a jar contains 5 blue marbles and 3 red marbles. suppose you choose a marble at random and do not replace it. then choose a seco
lina2011 [118]
\mathbb P(R_1\cap R_2)=\mathbb P(R_2\mid R_1)\mathbb P(R_1)

The probability of drawing a red marble on the first attempt is

\mathbb P(R_1)=\dfrac{\dbinom31}{\dbinom51}=\dfrac35

After the first marble is drawn, and we know it to be red, we're drawing the next marble from a pool with one less marble than before (i.e. conditioning on the event R_1). So

\mathbb P(R_2\mid R_1)=\dfrac{\dbinom21}{\dbinom71}=\dfrac27

And so

\mathbb P(R_1\cap R_2)=\dfrac35\cdot\dfrac27=\dfrac6{35}
4 0
3 years ago
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