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Setler79 [48]
3 years ago
11

An unknown sample is analyzed using paper chromatography using solvent X as mobile phase. One spot is observed after the paper i

s developed. The same unknown substance is re-analyzed using solvent Y as the mobile phase. This time, three spots are observed after the paper is visualized. Is the unknown sample a pure substance or a mixture? Explain your answer.
Chemistry
1 answer:
Montano1993 [528]3 years ago
5 0

Answer:

The substance is a mixture

Explanation:

The question lets us know that when solvent X was used as the mobile phase, we obtained only one spot. This may deceive us into thinking that the substance is pure since a pure substance has only one spot on a chromatogram.

However, the same substance yields three spots with solvent Y. This shows that the unknown sample is a mixture of substances and solvent X was unable to fully separate the mixture.

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NNADVOKAT [17]
Earthquakes and volcanic eruption
8 0
3 years ago
A 825 g iron block is heated to 352 degrees C and is placed in an insulated container (of negligible heat capacity) containing 4
Stella [2.4K]

Answer : The final equilibrium temperature of the water and iron is, 537.12 K

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of iron =  560 J/(kg.K)

c_1 = specific heat of water = 4186 J/(kg.K)

m_1 = mass of iron = 825 g

m_2 = mass of water = 40 g

T_f = final temperature of water and iron = ?

T_1 = initial temperature of iron = 352^oC=273+352=625K

T_2 = initial temperature of water = 20^oC=273+20=293K

Now put all the given values in the above formula, we get:

(825\times 10^{-3}kg)\times 560J/(kg.K)\times (T_f-625K)=-(40\times 10^{-3}kg)\times 4186J/(kg.K)\times (T_f-293K)

T_f=537.12K

Therefore, the final equilibrium temperature of the water and iron is, 537.12 K

8 0
3 years ago
Write a conversion factor that converts between moles of calcium ions in calcium phosphide, Ca3P2, and moles of Ca3P2.
cricket20 [7]

The conversion factor between moles of calcium ion and moles of Ca_3P_2 in  Ca_3P_2 would be 3 to 1.

<h3>Mole fraction</h3>

Ca_3P_2 if formed from 3 carbon atoms and 3 phosphate atoms according to the equation:

3Ca + 2P --- > Ca_3P_2

Thus, there are 3 moles of calcium in every 1 mole of  Ca_3P_2.

The conversion factor between moles of calcium and moles of  Ca_3P_2 will. therefore, be 3 to 1 or simply 3:1.

More on mole fractions can be found here: brainly.com/question/8076655

#SPJ1

6 0
2 years ago
I need help please i need to pass
goldfiish [28.3K]
Energy was released.
4 0
4 years ago
Read 2 more answers
HELP SOMEONE PLEASE I WILL GIVE BRAINLIST I NEED IT NOW PLZ! LOOK AT THE IMAGE ABOVE TO ANSWER
MAVERICK [17]

Answer:

its endothermic .

because your using a cooling process instead of a heating process if it was a heating process it would be exothermic

4 0
3 years ago
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