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Setler79 [48]
3 years ago
11

An unknown sample is analyzed using paper chromatography using solvent X as mobile phase. One spot is observed after the paper i

s developed. The same unknown substance is re-analyzed using solvent Y as the mobile phase. This time, three spots are observed after the paper is visualized. Is the unknown sample a pure substance or a mixture? Explain your answer.
Chemistry
1 answer:
Montano1993 [528]3 years ago
5 0

Answer:

The substance is a mixture

Explanation:

The question lets us know that when solvent X was used as the mobile phase, we obtained only one spot. This may deceive us into thinking that the substance is pure since a pure substance has only one spot on a chromatogram.

However, the same substance yields three spots with solvent Y. This shows that the unknown sample is a mixture of substances and solvent X was unable to fully separate the mixture.

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Answer:

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Explanation:

Assume you are using 1 L of water.

Then you are washing 4 L of salty oil.

1. Calculate the mass of the salty oil

Assume the oil has a density of 0.86 g/mL.

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3. Calculate the mass of salt in the spent water

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4. Mass of salt remaining in washed oil

Mass = 172 g - 150 g = 22 g  

5. Concentration of salt in washed oil

\text{Concentration} = \dfrac{\text{22 g}}{\text{3440 g}} \times 100 \, \% = \mathbf{0.64 \, \%}\\\\\text{The concentration of salt in the washed oil is $\large \boxed{\mathbf{0.64 \, \%}}$}

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