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3 years ago

HELP SOMEONE PLEASE I WILL GIVE BRAINLIST I NEED IT NOW PLZ! LOOK AT THE IMAGE ABOVE TO ANSWER

Chemistry

1 answer:

MAVERICK [17]3 years ago

4 0

Answer:

its endothermic .

because your using a cooling process instead of a heating process if it was a heating process it would be exothermic

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Which elements do not have a set number of valence electrons?

laila [671]

Answer:

the answer would be B. hope this helps!

Explanation:

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3 years ago

A rectangle solid of unknown density is 5 m long two meters high and 4 meters wide. The mass of this solid is 300 grams. Find th

aksik [14]

D= M/V so, D=300/40 wich is 7.5 so D= 7.5g/m3

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3 years ago

Why does every chemical reaction require

Lana71 [14]

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4 years ago

Read 2 more answers

The density of a certain type of plastic is 0.81 g/cm3. If a sheet of this plastic is 10.0 m long, 1.0 m wide, and 1 cm thick, w

crimeas [40]

<u>Answer:</u> The mass of plastic sheet is $8.1\times 10^4g$

<u>Explanation:</u>

The plastic sheet is in the form of cuboid. To calculate the volume of cuboid, we use the equation:

$V=lbh$

where,

V = volume of cuboid

l = length of cuboid = 10.0 m = 1000 cm (Conversion factor: 1 m = 100 cm)

b = breadth of cuboid = 1.0 m = 100 cm

h = height of cuboid = 1 cm

Putting values in above equation, we get:

$V=1000\times 100\times 1=10^5cm^3$

To calculate mass of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

We are given:

Density of plastic sheet = $0.81g/cm^3$

Volume of plastic sheet = $10^5cm^3$

Putting values in equation 1, we get:

$0.81g/cm^3=\frac{\text{Mass of plastic sheet}}{10^5cm^3}\\\\\text{Mass of plastic sheet}=8.1\times 10^4g$

Hence, the mass of plastic sheet is $8.1\times 10^4g$

8 0

4 years ago

a 15.00 mL sample of an unknown HClO4 solution requires titration with 25.64 mL of 0.2000 M NaOH to reach equivalence point. wha

Veronika [31]

Answer:

V₁ = 0.342 M

Explanation:

Given data:

Volume of HClO₄ = 15.00 mL

Volume of NaOH = 25.64 mL

Molarity of NaOH = 0.2000 M

Molarity of HClO₄ = ?

Solution:

Formula:

M₁V₁ = M₂V₂

V₁ = M₂V₂ /M₁

V₁ = 0.2000 M ×25.64 mL /15.00 mL

V₁ = 5.128 M. mL /15.00 mL

V₁ = 0.342 M

5 0

3 years ago