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aleksandrvk [35]
3 years ago
13

Molecular formula of ammonia

Chemistry
1 answer:
ser-zykov [4K]3 years ago
5 0
The answer is NH3
Hope this helps!
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Question 6 (0.04 points)
Bingel [31]
I think it’s C
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3 years ago
A 20.38 gram sample of cobalt is heated in the presence of excess sulfur. A metal sulfide is formed with a mass of 31.47 g. Dete
Viefleur [7K]

Answer: The empirical formula of the metal sulfide is CoBr_{2}.

Explanation:

Given: Mass of metal = 20.38 g

Mass of metal sulfide = 31.47 g

Moles is the mass of a substance divided by its molar mass.

So, moles of cobalt (molar mass = 59 g/mol) are as follows.

Moles = \frac{mass}{molarmass}\\= \frac{20.38 g}{59 g/mol}\\= 0.345 mol

Moles of bromine (molar mass = 80 g/mol) are as follows.

Moles = \frac{(31.47 - 20.38) g}{80 g/mol}\\= \frac{11.09 g}{80 g/mol}\\= 0.138 mol

Now, the ratio of number of moles of cobalt and number of moles of bromine are as follows.

Moles of Co : Moles of Br = 1 : 2

Hence, the empirical formula is CoBr_{2}.

Thus, we can conclude that the empirical formula of the metal sulfide is CoBr_{2}.

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