The team won 36 games. 0.75 multiplied by 48.

Carry out the binomial expansion in the numerator:

Then the 9⁴ terms cancel each other, so in the limit we have

Since <em>h</em> is approaching 0, that means <em>h</em> ≠ 0, so we can cancel the common factor of <em>h</em> in both numerator and denominator:

Then when <em>h</em> converges to 0, each remaining term containing <em>h</em> goes to 0, leaving you with

or choice C.
Alternatively, you can recognize the given limit as the derivative of <em>f(x)</em> at <em>x</em> = 9:

We have <em>f(x)</em> = <em>x</em> ⁴, so <em>f '(x)</em> = 4<em>x</em> ³, and evaluating this at <em>x</em> = 9 gives the same result, 2916.
Answer:
27 by 27
Step-by-step explanation:
Let the sides be x and y. The problem is essentially asking:
Given 2(x+y)=108, maximize xy.
We know that x+y=54. By the Arithmetic Mean - Geometric Mean inequality, we can see that
. Substituting in x+y=54, we get
, meaning that
. Equality will only be obtained when x=y (in this case it will generate the maximum for xy), so setting x = y, we can see that x = y = 27. Hence, 27 is the answer you are looking for.
I would say infinitely many
Answer:
zh
Step-by-step explanation: