Both a discount and decrease will make the cost the same which is $225 for the object. I think that's what your asking. I'm sorry if it is not that helpful.
The answer is a.0.32 km.
The speed that a tsunami can travel is modeled by the equation is s = 356√d.
It is given:
s = 200 km/h
d = ?
Now, let's substitute s in the equation and find d:
s = 356√d
200 = 356√d
√d = 200 ÷ 356
√d = 0.562
Now, let's square both sides of the equation:
(√d)² = (0.562)²
d = (0.562)² = 0.316 ≈ 0.32
Therefore, <span> the approximate depth (d) of water for a tsunami traveling at 200 kilometers per hour is 0.32 km.</span>
Answer:
= -21 - 15g
Step-by-step explanation:
Given that:
= -3(7+5g)
By simplifying
As "-" sign will invert the inner signs:
= -21 - 15g
I hope it will help you!!
Answer:
y+3 = -6(x+9)
Step-by-step explanation:
m(x-x1)= (y-y1)
-6[x-(-9)] = [y-(-3)]
-6(x+9) = y+3
.....
