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Kitty [74]
3 years ago
15

Write an equation in point-slope form of the line that passes through the given point and has the given slope. (12, 5); m = -3

Mathematics
1 answer:
givi [52]3 years ago
7 0

Answer:

y - 5 = -3(x - 12)

Step-by-step explanation:

Point slope form is: y - y1 = m(x - x1), where (x1, y1) is a point on the line, and m is the slope of the line.

Plug in the point and the slope:

y - y1 = m(x - x1)

y - 5 = -3(x - 12)

So, y - 5 = -3(x - 12) is the equation in point slope form of the line.

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What is the solution to the system of equations
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Answer:

Y = -8.17

X= -4.936

For the first one

Step-by-step explanation:

4x=26+6y

X = 6.5+1.5y

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3 years ago
What is this equation called?
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The left sides of the equations are the same and the right sides of the equations are different, therefore the system of equations is inconsistent.

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3 years ago
Use Remainder Theorem to determine if x-2 is a factor of the polynomial f(x)=3x^5 - 7x^3 -
morpeh [17]

<u>Answer:</u>

(x - 2) is not a factor of f(x)  = 3x^5 - 7x^3 -  11x^2 + 2

<u>Step-by-step explanation:</u>

According to the Remainder Theorem, when a polynomial f(x) is divided by a term (x - r), then the remainder must be f(r).

So first we will divide f(x) by (x - 2) using long division to get:

(3x^5 - 7x^3 -  11x^2 + 2) / (x - 2)

= 3x^4 + (6x^4 - 7x^3 - 11x^2 + 2) / (x-2)

= 3x^4 + 6x^3 + (5x^3-11x^2+2) / (x - 2)

= 3x^4 + 6x^3 + 5x^2 (-x^2 + 2) / (x - 2)

= 3x^4 + 6x^3 + 5x^2 -x -2 - (2) / (x -2)

= \frac{-2 + 3x^{5} - 7x^{3} - 11x^{2} + 2x}{x - 2} - 2

Therefore the remainder is -2.

Now check x = 2 for 3x^5 - 7x^3 -  11x^2 + 2:

3(2)^5 - 7(2)^3 -  11(2)^2 + 2 = -2

The Remainder Factor theorem also states that if (x - r) is a factor of f(x) then f(r) must be 0.

So we found that f(2) = -2, therfore (x - 2) is not a factor of f(x) .


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