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Drupady [299]
2 years ago
9

Help please its for school

Mathematics
2 answers:
Alex2 years ago
8 0

Answer:

68.302

Step-by-step explanation:

68302/1000=68.302

hope this helps :)

Lelu [443]2 years ago
5 0

Answer:

34151

Step-by-step explanation:

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Use the information in the diagram to determine the height of the tree. The diagram is not a scale
dusya [7]
In the given diagram, we can note that the tree divides the hypotenuse of the triangle as well as the side where the tree is based into halves.

In a triangle, when a line is drawn joining between the midpoints of two sides, this line is always parallel to the third side and equals half its length.

Applying this concept to the given diagram here, we will find that the tree is joining the midpoints of two sides of the triangle. this means that the tree is parallel to the building and the height of the tree is half the height of the building.

Therefore:
height of tree = 0.5 * 120 = 60 ft
6 0
3 years ago
one market vendor says to the other: "if i were to give you 10 apples, we'd both have the same number of apples. but if you were
Allushta [10]

Answer:

One market vendor has 70, and the other has 50.

Step-by-step explanation:

Hope I helped!

4 0
3 years ago
If the expression 4c + 2b + 4d is subtracted from 3c + 4b + 5d then the answer will be<br>​
kirill [66]

Answer:

1c 2b 1d

Step-by-step explanation:

did the math

6 0
3 years ago
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2 7/12 as a decimal<br><br> I forgottttttthelp
MariettaO [177]

Answer:

2.58333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333331

Step-by-step explanation:

5 0
3 years ago
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A business was valued at £80000 at the start of 2013. In 5 years the value of this business raised to £95000. this is equivalent
Yuri [45]

the yearly increase of x% assumes is compounding yearly, so let's use that.

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill &\£95000\\ P=\textit{original amount deposited}\dotfill &\£80000\\ r=rate\to r\%\to \frac{r}{100}\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &5 \end{cases}

95000=80000\left(1+\frac{~~ \frac{r}{100}~~}{1}\right)^{1\cdot 5}\implies \cfrac{95000}{80000}=\left( 1+\cfrac{r}{100} \right)^5 \\\\\\ \cfrac{19}{16}=\left( 1+\cfrac{r}{100} \right)^5\implies \sqrt[5]{\cfrac{19}{16}}=1+\cfrac{r}{100}\implies \sqrt[5]{\cfrac{19}{16}}=\cfrac{100+r}{100} \\\\\\ 100\sqrt[5]{\cfrac{19}{16}}=100+r\implies 100\sqrt[5]{\cfrac{19}{16}}-100=r\implies 3.5\approx r

4 0
2 years ago
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