The probability of the sample is 0.5 or 50%
<u>Explanation:</u>
Given:
Mean, μ = 20
Standard deviation, δ = 1.3
Probability of sample being less than 20.1 = ?
P (x < 20.1) = 20.1 - μ / δ √n
P (x < 20.1) = 
= 0.0098
P( x < 20.1) = P(z < 0.0098)
P (z < 0.0098) = 0.5
The value of P is found out using a z score table.
Therefore, probability of the sample is 0.5 or 50%
<h3><em><u>given</u></em><em><u>;</u></em></h3>
<em><u>5,870,000,000,000 miles.</u></em>
<h3><em><u>to</u></em><em><u> </u></em><em><u>find</u></em><em><u>:</u></em></h3>
<em><u>The distance light travels in 100 years</u></em><em><u>.</u></em>
<h3><em><u>solution</u></em><em><u>:</u></em></h3>
<em><u>The distance of the light travels in 100 years is:</u></em>
<em><u>5,870,000,000,000 × 100 miles.</u></em>
<em><u>= 587,000,000,000,000 miles</u></em>
<em><u>= 587 × 10</u></em><em><u>^</u></em><em><u>12 miles.</u></em>
<em><u>answer</u></em><em><u>=</u></em><em><u> </u></em><em><u>option</u></em><em><u> </u></em><em><u>d</u></em>
The first thing to notice with this question is that the volume of the tank is given in cm3 yet the rate at which the water leaks is in litres, so a conversion of units will be neccessary. We know that there are 1000cm3 for every litre so 45000cm3 is equivilent to 45 litres (45,000/1000 = 45). So what do we know now? Well the tank of water contains 45 litres, and every minute 0.75 litres is lost, so our objective is to find out how many miuntes go by before the tank is empty. In other words how many 0.75s go into 45, luckily division can help us out. 45/0.75 = 60 minutes.
Mark brainliest please
Hope this helps you
We are given a problem that can be solved using a system of linear equations. Let A, be the number of adults, and S the number of students. Since there are in total 142 people and there were two days, this means that the sum of the number of adults and the number of students must be 284, which can be written mathematically as follows:

This is our first equation. The second equation is found using the total sales of $1948. Since the ticket per adult is $8 and per student is $5, we have the following equations:

To solve this equation we will solve for A in equation (1), by subtracting S to both sides;

Now we will replace this value in equation (2):

Now we will apply the distributive property:

Addins like terms:

Subtracting 2272 to both sides;

Dividing both sides by -3:

Now we replace this value in equation (1), where we have already solved for A:

Therefore, there were sold 108 student tickets and 140 adult tickets.
9514 1404 393
Answer:
136.96754 shares, or maybe 136 shares
Step-by-step explanation:
At a cost of $146.02 per share, $20,000 will buy ...
$20,000 / (146.02/share) = 136.96754 shares
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Some accounts will let you purchase partial shares; others require you purchase whole shares. $20,000 is enough to pay for 136.96754 shares, but you may be able to purchase only 136 shares. (You would have $141.28 in cash remaining after that transaction.)
Some accounts manage shares in multiples of 0.001 shares; others may use more decimal places. Above, we have shown the quantity that spends the entire $20,000. Using fewer decimal places will leave some cash remaining.
We have assumed you're not paying any brokerage fees or loads that would reduce the amount of money that actually purchases shares.
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<em>Additional comment</em>
Whenever you buy anything, the cost of more than one of it is the unit price times the number of units. (Quantity discounts may apply.) In like fashion, the cost of multiple shares of stock is the single-share cost multiplied by the number of shares. As with all multiplication relations, a corresponding division relation is <em>the number of shares is the total cost divided by the cost per share</em>.