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3 years ago

[Help Asap, Will Mark Brainliest] Question is in the image.

Mathematics

1 answer:

Mazyrski [523]3 years ago

6 0

Answer:

y = 30

z = 115

Step-by-step explanation:

z° + 65° = 180°

(Exterior Angles on the same side of transversal)

z° = 180° - 65°

z° = 115°

z = 115

(5y - 85)° + z° = 180°

(Linear pair angles)

(5y - 85)° + 115° = 180°

(5y - 85)° = 180° - 115°

(5y - 85)° = 65°

5y - 85 = 65

5y = 65 + 85

5y = 150

y = 150/5

y = 30

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A survey found that the American family generates an average of 17.2 pounds of glass garbage trash each year. Assume the standar

SIZIF [17.4K]

Answer: 0.8137

Step-by-step explanation:

As per given , we have

$\mu= 17.2\ ,\ \sigma=2.5$

Sample size : n= 47

Let $\overline{X}$ be the sample mean o.

Then, the probability that the mean of a sample of 47 families will be between 16.6 and 17.6 pounds will be :

$P(16.6$

$=P(-1.645$

[∵ $z= \dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}$ ]

$=P(z$

$=0.8636793-(1- 0.9500151)$ [By using p-value calculator]

$=0.8636793-0.0499849=0.8136944\approx0.8137$

Hence, the probability that the mean of a sample of 47 families will be between 16.6 and 17.6 pounds= 0.8137

6 0

4 years ago

You eat a 25° slice of your chocolate birthday cake. What is the volume

Marysya12 [62]

Answer:

848.23

Step-by-step explanation:

Step 1: Find Volume Of The The Cake

Volume = $\pi r ^{2} h$

Evaluate: ~848.23

Step 2: Find The Part The Was Eaten:

Full Circle: 360

Eaten = 25

Part: 25/360 = 14.4

Set 3: Find Volume Eaten:

14.4/848.23 = 58.90

8 0

3 years ago

ASAP please, find x

Jet001 [13]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Question is down below

mr Goodwill [35]

The correct answer would be B.

7 0

4 years ago

Read 2 more answers

At a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective pa

11Alexandr11 [23.1K]

Answer:

Probability that fewer than 2 of these parts are defective is 0.604.

Step-by-step explanation:

We are given that at a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective parts 19% of the time.

A random sample of 7 parts produced by this machine is chosen.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 7 parts

r = number of success = fewer than 2

p = probability of success which in our question is % of defective

parts produced by one of the machine, i.e; 19%

LET X = Number of parts that are defective

So, it means X ~ Binom(n = 7, p = 0.19)

Now, probability that fewer than 2 of these parts are defective is given by = P(X < 2)

P(X < 2) = P(X = 0) + P(X = 1)

= $\binom{7}{0}\times 0.19^{0} \times (1-0.19)^{7-0}+ \binom{7}{1}\times 0.19^{1} \times (1-0.19)^{7-1}$

= $1 \times 1 \times 0.81^{7} +7 \times 01.9^{1} \times 0.81^{6}$

= 0.604

Therefore, the probability that fewer than 2 of these parts are defective is 0.604.

8 0

3 years ago