Answer:
x=103/265 y=18/53
Step-by-step explanation:
5x -9y=1-----------(i)
-7x+2y=-5-----------(ii)
Multiplying eq 1 with 7 gives
35x-63y=7---------eq(iii)
Multiplying eq 2 with 5 gives
-35x+10y=-25--------eq(iv)
adding eq 3 qnd eq 4
35x-63y-35x+10y=7-25
-53y=-18
y=18/53--------eq5
Putting the value of y from eq 5 in eq 1
5x-9(18/53)=-5
5x- 162/53=-5
5x=-5 +162/53
5x= -265+162/53
5x=103/53
x=103/265
Hello again Charlesbabegirl! :)
First of all, let's say that the sum of all internal angles of a triangle is always 180°
This means that if you add up angles A, B and C you get 180 but we should find first the value of x by setting up a proportion of this type:
A + B + C = 180
12x + 12 + 15 + 3x + 18 = 180
Move all the known terms (those that don't have x) to the right with changed sign.
12x + 3x = 180 - 12 - 15 - 18
15x = 135
Divide both terms by 15
x = 9
Then plug the value of x...
m∠A = 12(9) + 12 = 108+12 = 120°
m∠C = 3(9) + 18 = 27 + 18 = 45°
Hope I helped and let me know if I was right!
Consider two <u>right triangles</u>:
1. ΔABC with <u>vertices</u> A(0,0), B(0,2), C(6,0). Then AB is perpendicular to AC and AB=2 units (<u>vertical leg</u>), AC=6 units (<u>horizontal leg</u>).
2. ΔXYZ with vertices X(6,-10), Y(6,0), Z(36,-10). Then XY is perpendicular to XZ and XY=10 units (vrrtical leg), XZ=30 units (horizontal leg).
The equation of the line BC is
Check whether points Y and Z lie on this line:
Y(6,0): - true;
Z(36,-10): - true.
Answer: the hypotenuses of these two triangles could lie along the same line
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