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Nikolay [14]
3 years ago
9

a bag of a certain type of sand weighs 42 pounds and has a volume of 0.5 cubic feet. a sandbox has a volume of 16 cubic feet. ap

proximately how many pounds of sand will it take to fill the sandbox
Mathematics
1 answer:
Anna71 [15]3 years ago
7 0

Answer:32

Step-by-step explanation:I divided 16 by 0.5

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Line segment AB is drawn in the coordinate plane. Carlos graphed the set of points that are the same distance from both point A
Maru [420]

Answer:

Carlos graphed the perpendicular bisector of the segment that joins the two points. (a line)

Step-by-step explanation:

Carlos graphed the set of points that are equidistant from both point A and point B.

Carlos graphed the perpendicular bisector of the segment that joins the two points. (a line)

7 0
3 years ago
Solve the system of equations by elimination. Show your work. i’ll give brainliest
My name is Ann [436]

Answer:

x = 5

y = 4

Step-by-step explanation:

multiply the second equation by -1 and add the first equation to eliminate "x"

4x+6y=44\\-4x-2y=-28
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y=16/4 =4

Replace "y" in the first equation:

4x+6(4)=44

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4x=44-24

x=20/4=5

Hope this helps

5 0
2 years ago
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Please help I'm not able to solve this I have tried so many times and the answers I have gotten are all wrong. Please help!! If
goblinko [34]

Answer:

The diameter will be given by 50 cm ÷ 3.142 = 15.9134 cm

The radius will be 15.9134 ÷2 = 7.9567 cm or about 7.96 cm

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3 years ago
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Find the slope of the line on the graph write you answer as a fraction or a whole number not a mixed number or decimal
marysya [2.9K]
The slope is roughly -6/1
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6 0
3 years ago
there are about 25000000000 red boold cells in the average adult. About how many adult would it take to have a total googol of r
IRISSAK [1]
A googol is 1.0*10^100.  there are <span>25000000000 RBC in the average adult.  
The number of adults equals
1.0*10^100 / </span><span>25000000000
=</span>400000000000000000000000000000000000000000000000000000000000000000000000000000000000000000
(=10^100/(25*10^9)=4*10^89)
6 0
3 years ago
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