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2 years ago

654. Представьте в виде произведения степень:

Mathematics

1 answer:

anygoal [31]2 years ago

5 0

Answer:

Whatever this means.

Step-by-step explanation:

654. Present the degree in the form of a product:

1000;

g) ka; j) (m + 2)

6) 12

A) 60t:

3) aw; l) (a - 7;

B) 15.

i) x2; m) (x + yy.

Hope this helps with anyone......

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Can y'all plz help me with this

schepotkina [342]

Answer:

It's rise/run.

May or not be right but I hope it helps!

I added the attachment.

6 0

2 years ago

All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$

In which

$(A \cup B) = a + b + (A \cap B)$

65% were found to be proficient in both reading and mathematics.

This means that $A \cap B = 0.65$

78% were found to be proficient in mathematics

This means that $B = 0.78$

$B = b + (A \cap B)$

$0.78 = b + 0.65$

$b = 0.13$

85% of the students were found to be proficient in reading

This means that $A = 0.85$

$A = a + (A \cap B)$

$0.85 = a + 0.65$

$a = 0.20$

Proficient in at least one:

$(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98$

What is the probability that the student is proficient in neither reading nor mathematics?

$(A \cup B) + C = 1$

$C = 1 - (A \cup B) = 1 - 0.98 = 0.02$

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0

2 years ago

Please I need answer right now ppleassssee<br><br>D. -1/4+-2/3<br>with explanation pleaseeee

Masja [62]

Answer:

1 - 1/3

Step-by-step explanation:

Since 1/2 * 2/3 = 1/3, it should be the case that 1/3 divided by 2/3 gives 1/2 and that 1/3 divided by 1/2 gives 2/3. To divide fractions, we multiply the numerator by the reciprocal of the denominator, where the reciprocal of a number just interchanges the numerator and denominator of the number.

5 0

2 years ago

A construction manager weighs a bundle of 9 identical bricks and a 7 pound concrete block. The bundle weighs 30 pounds.

denis23 [38]

Answer:

30 = 9x + 7

Step-by-step explanation:

The total weight of the bundle = 30 pounds

The weight of the bricks = x pounds

But he carried 9 bricks = 9x pounds

He also carried additional 7 pounds of concrete block.

An equation to show the total weight he carried is

30 pounds = (9x + 7) pounds

Since 9x represents the total weight of the bricks he carried

7 represents the weight of the concrete block

And 30 pounds represents the total weight of everything he carried.

6 0

2 years ago

Help !!!!!!!!!!!!!!!

xxMikexx [17]

Answer:

I hate maths it's a boring subject

5 0

2 years ago