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crimeas [40]
3 years ago
9

What property is 2 + (8 + 3) = (2 + 8) + 3​

Mathematics
1 answer:
spayn [35]3 years ago
5 0

Answer:

Step-by-step explanation:

The property is commutative property because the numbers can be moved or swapped without making the answer different.

Not sure

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Factor: 6x^2 + 11x + 3<br><br> Write each factor in standard form.
yKpoI14uk [10]
The answer is: (2x+3) (3x+1)
8 0
3 years ago
A small moving box has a volume of 2304 inches cubed and length of 16 inches. The box's width and height are the same. Write the
lisabon 2012 [21]

Answer:

<em>V = 16x² </em>

<em>Width = 12in</em>

<em>Height = 12in</em>

Step-by-step explanation:

Volume of the box is expressed as;

V = Length *Width * height

Given

Length = 16in

Width = x

Height = x

The volume of the box will be expressed as;

V = 16 * x * x

<em>V = 16x² (This gives the required equation)</em>

To get x:

We are given

V = 2304in³

Substitute;

2304 = 16x²

x² = 2304/16

x² = 144

x= √144

x = 12

<em>Hence the width and the height are both 12inches since they are the same.</em>

<em></em>

For the sma

8 0
3 years ago
A degree is larger than 30 arc minutes. ...?<br><br> true or false
oksano4ka [1.4K]
It is a completely true statement that a <span>degree is larger than 30 arc minutes. The correct option among the two options that are given in the question is the first option. 30 arc minutes is almost equal to 1/2 degree. I hope that this is the answer that you were looking for and the answer has actually come to your great help.</span>
7 0
3 years ago
Read 2 more answers
A movie theater has a seating capacity of 329. The theater charges $5.00 for children, $7.00 for students, and $12.00 of adults.
kipiarov [429]

Answer:

170 children

74 students

85 adults

Step-by-step explanation:

Given

Let:

C = Children; S = Students; A = Adults

For the capacity, we have:

C + S + A = 329

For the tickets sold, we have:

5C + 7S + 12A = 2388

Half as many as adults are children implies that:

A = \frac{C}{2}

Required

Solve for A, C and S

The equations to solve are:

C + S + A = 329 -- (1)

5C + 7S + 12A = 2388 -- (2)

A = \frac{C}{2} -- (3)

Make C the subject in (3)

C = 2A

Substitute C = 2A in (1) and (2)

C + S + A = 329 -- (1)

2A + S + A = 329

3A + S = 329

Make S the subject

S = 329 - 3A

5C + 7S + 12A = 2388 -- (2)

5*2A + 7S + 12A = 2388

10A + 7S + 12A = 2388

7S + 22A = 2388

Substitute S = 329 - 3A

7(329 - 3A) + 22A = 2388

2303 - 21A + 22A = 2388

2303 +A = 2388

Solve for A

A = 2388 - 2303

A = 85

Recall that: C = 2A

C = 2 * 85

C = 170

Recall that: S = 329 - 3A

S = 329 - 3 * 85

S = 329 - 255

S = 74

Hence, the result is:

C = 170

S = 74

A = 85

8 0
3 years ago
PLEASE HELP! TWO PROBLEMS!!
MrRissso [65]

1) x=−2 2) y=−6 Hopefully that helps you ❤.

6 0
3 years ago
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