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larisa86 [58]
3 years ago
5

Taylor and Katy repeatedly toss a fair coin. Katy wins if heads are thrown, Taylor wins if tails are thrown, and the game ends w

hen someone has won three times. Katy is currently behind 1 to 2. The chance Katy wins is:
Mathematics
1 answer:
ehidna [41]3 years ago
5 0

Answer:

25%

Step-by-step explanation:

In order to find the chance/probability that Katy wins we need to first find the probability of her winning a single coin toss and then multiply it twice. This is because Katy has 1 win already and needs two more win the entire game. Since a coin toss only has 2 options and only 1 of those outcomes will cause Katy to win, then this means that the probability of Katy winning is 1/2 or 50%. Now we can multiply this probability twice to get the probability of Katy winning the entire game

1/2 * 1/2 = 1/4 or 25%

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Hailey is a high school basketball player. In a particular game, she made some three point shots and some free throws (worth one
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Let x represent the number of three point shots that Hailey made.

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Which of the following are solutions to the equation below?
scoundrel [369]

Answer:

The correct options for the solution values are:

  • x=2\sqrt{2}-5
  • x=-2\sqrt{2}-5

Step-by-step explanation:

Given the expression

x^2+10x+25=8

Subtract 25 from both sides

x^2+10x+25-25=8-25

Simplify

x^2+10x=-17

Add 25 or 5² to both sides

x^2+10x+5^2=8

as

x^2+10x+5^2=\left(x+5\right)^2

so the expression becomes

\left(x+5\right)^2=8

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

solve

x+5=\sqrt{8}

Subtract 5 from both sides

x+5-5=2\sqrt{2}-5

x=2\sqrt{2}-5

solve

x+5=-\sqrt{8}

Subtract 5 from both sides

x+5-5=-2\sqrt{2}-5

x=-2\sqrt{2}-5

Therefore, the solution to the equation

x=2\sqrt{2}-5,\:x=-2\sqrt{2}-5

Hence, the correct options for the solution values are:

  • x=2\sqrt{2}-5
  • x=-2\sqrt{2}-5

6 0
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