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Licemer1 [7]
3 years ago
13

Whats 1 2/3 as a improper fraction? *(Help)

Mathematics
2 answers:
morpeh [17]3 years ago
5 0
5/3

......................
steposvetlana [31]3 years ago
5 0
The answer is 5/3 op
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How do you substitute x+y=2 3x+2y=5
Monica [59]
Here's how you solve this.  So, x+y=2, right?  Let's isolate x.  x+y-y=2-y.  x=2-y.  NOW, if x=2-y, in 3x+2y=5, we can REPLACE x with 2-y and use it to solve for y!  3x+2y=5.  3(2-y)+2y=5.  (3*2)+(3*-y)+2y=5.  6+(-3y)+2y=5.  6+(-y)=5.  6+(-y)-6=5-6.  -y=-1.  -y/-1=-1/-1.  y=1.

So, if y=1, we can substitute that back into either equation--but let's go with the easier one, x+y=2.  x+1=2.  x+1-1=2-1.  x=1.  1+1=2, so that works; let's check the other equation.  3(1)+2(1)=5.  3+2=5.  5=5.  That's correct!

Answer: x=1, y=1
4 0
3 years ago
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I need some help on this! i need my grade to go up
Kaylis [27]
3rd one I think tho it may not be accurate
4 0
2 years ago
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a recipe for 4 servings of mashed potatoes calls for 1 1/3 cups of potato flakes and 1 cup of boiling water. if james wants to m
ElenaW [278]
Potato Flakes: 2 cups
Boiling Water: 1 1/2 cups
3 0
4 years ago
There are 12 marbles in a box. 8 are purple, and 4 are green. What is the probability of picking a purple marble and then a gree
Bad White [126]

Answer: 8/33

Step-by-step explanation:

So the probability of picking a purple marble is 8/12, after that there are 11 marbles left in the box

Now the probability of picking a green marble without placing the first marble back is 4/11

So the probability of doing both is 8/12 x 4/11 = 8/33

8 0
2 years ago
Which system is equivalent to the system shown and could be used to solve the system of equations correctly using the eliminatio
Bumek [7]

Answer:

The solution is (2, -2)

Step-by-step explanation:

In order to solve this, multiply the second equation by -5 and then add through.

5x - 4y = 18

-5x - 15y = 20

------------------

-19y = 38

y = -2

Now that we have the value of y, we can solve for x.

x + 3y = -4

x + 3(-2) = -4

x - 6 = -4

x = 2

5 0
3 years ago
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