Ahhh bet your a female right?
Answer:
Step-by-step explanation:
2x = 3y + 1/2
standard : Ax + By = C
2x = 3y + 1/2....multiply everything by 2 to get rid of the fractions
4x = 6y + 1 ....subtract 6y from both sides
4x - 6y = 1 <==
slope intercept : y = mx + b
2x = 3y + 1/2....subtract 1/2 from both sides
2x - 1/2 = 3y....divide everything by 3
2/3x - 1/6 = y...rearrange
y = 2/3x - 1/6 <===
C; the first and last letters in each group is connected, after U and V being first and last it should be W and X being first and last.
Answer
Find out the how many pounds of metal are in 1,950 lb of ore .
To proof
let us assume that the pounds of metal are in 1,950 lb of ore be x .
As given
In an ore, 9.8% of its total weight is metal.
ore weight = 1,950 lb
9.8% is written in the decimal form

= 0.098
Than the equation becomes
x = 0.098 × 1950
x = 191.1 pounds
Therefore the 191.1 pounds of metal are in 1,950 lb of ore .
Hence proved