Step-by-step explanation:
ED is greater than BC
the line from B to ED ^ (which i drew ) the point it touches ED name it X. so EX will be 2 ( ED-BC)(6-4).
then u have a triangle. EX, XB and EB.
you have length of EX(2) and u have hypotenuse. so u can calculate XB using Pythagoras theorem.
15.1²=2²+XB²
15.1²-2²=XB²
224.01=XB²
XB=14.97
since XB and DC are parallel ( a rectangle is forming XBCD) so DC is also 14.97
Solving the inequality given algebraically, the solution of the inequality for the value of m is:
<u>m < -4 OR m > 3</u>
<em><u>Given the following </u></em><em><u>inequality</u></em><em><u>,</u></em>
<em><u /></em>
or
4m + 3 > 15
Let's solve algebraically for the value of m in both inequality statements given.
Or
4m + 3 > 15
4m + 3 - 3 > 15 - 3
4m > 12
m > 3
Therefore, solving the inequality given algebraically, the solution of the inequality for the value of m is:
<u>m < -4 OR m > 3</u>
<u></u>
<u></u>
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Answer:
max. height = 240
Step-by-step explanation:
Function should be h(t ) = - 16t² + 96t
find the zeros by solving h(t) = 0
- 16t² + 96t = 0 ( take out common factor - 16t )
- 16t(t - 6) = 0
equate each factor to zero and solve for t
- 16t = 0 ⇒ t = 0
t - 6 = 0 ⇒ t = 6
the maximum vertex is at the midpoint of the zeros
t = = 3
h(3) = (- 16 × 3) + (96 × 3) = - 48 + 288 = 240 ← max. height