Answer:
yes
Step-by-step explanation:
Answer:
h ≈ 11.9
Step-by-step explanation:
Since the triangle is right we can use the cosine ratio to find h
cos24° =
= 
Multiply both sides by 13
13 × cos24° = h
⇒ h = 11.9 cm ( to 1 dec. place )
Answer:
181 mi^2
Step-by-step explanation:
Dimensions of large rectangle, on the left, are 6 mi by 8 m; area is 48 m^2;
Dimensions of small rectangle, in the middle of the diagram, are 4 mi by 5 mi, or 20 mi^2; area is 20 mi^2.
Dimensions of circle: r = 12 mi; area of quarter circle is (1/4)(3.14)(12 mi)^2, or 113 mi^2.
Total area is 113 mi^2 + 20 mi^2 + 48 mi^2, or 181 mi^2
It depends on how well the rest of the class does. A safe bet is usually a 93 for an A.
Answer:
a) 0.172
b) 0.167
c) 0.1404
Step-by-step explanation:
Margin of error, E = 
here,
p = probability of the event
n = sample size
a) n = 30
p = 10 ÷ 30 = 0.333
Therefore,
E = 
= 2 × 0.0861
= 0.172
b) n = 30
p = 21 ÷ 30 = 0.7
Therefore,
E = 
= 2 × 0.0836
= 0.167
c) n = 30
p = 22 ÷ 50 = 0.44
Therefore,
E = 
= 2 × 0.0702
= 0.1404