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Temka [501]
3 years ago
11

PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU B

RAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!!
PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!!

Mathematics
2 answers:
solniwko [45]3 years ago
6 0

Answer:

y = -14, x = -17

Step-by-step explanation:

-2(y-3)+3y=-8

-2y+6+3y=-8

y+6=-8

-6.     -6

y=-14

x = y-3

x = -14-3

x = -17

kozerog [31]3 years ago
5 0
-1 ? Sorry if I’m not correct but I believe it’s one
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2 years ago
Pi/6 is the reference angle for:<br><br> 3pi/6<br><br> 5pi/6<br><br> 13pi/6<br><br> 8pi/6
Elanso [62]

Answer:

\frac{5\pi}{6}, \frac{13\pi}{6}

Step by step

Remember, a reference angle is a positive acute angle that represents an angle θ of any measurement.

a)

\frac{3\pi}{6}=90^\circ, then its reference angle is \frac{\pi}{2}

b)

\frac{5\pi}{6}=150^ \circ is in the second cuadrant, then its reference angle is 180^ \circ -150^{\circ}=30^{\circ}=\frac{\pi}{6}

c)

\frac{13\pi}{6}=390^\circ=360^\circ+30^\circ, then it is in the first cuadrant and the reference angle is 30^\circ =\frac{\pi}{6}.

d)

\frac{8\pi}{6}=240^\circ and it is in the third cuadrant, then its reference angle is 240^\circ -180^\circ=60^\circ=\frac{\pi}{3}

5 0
3 years ago
Triangle PQR has vertices P(–2, 6), Q(–8, 4), and R(1, –2). It is translated according to the rule (x, y) → (x – 2, y – 16). Wha
Rudik [331]
The point P has coordinates (x,y) = (-2,6) so x = -2 and y = 6

Replace x and y with those values into the rule given
So,
(x,y) ---> (x-2, y-16)
turns into
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P = (-2,6)
P ' = (-4,-10) 

The answer is -10 because your teacher just wants the y coordinate of point P'
4 0
3 years ago
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