How do I find the Q1 and Q3?<br><br>
0,0,1,2,2,3,4,4,4,4,5,6,6,7,7
Angelina_Jolie [31]
Answer:
Q1 = 2
Q3 = 6
Step-by-step explanation:
Mathematically, we have
Q1 = (n + 1)/4 th term
where n is the number of terms
By the count, we have n as 15
Q1 = (15 + 1)/4
Q1 = 4th term
Looking at the arrangement, the 4th term is 2
For Q3
Q3 = 3(n + 1)/4 th term
n = 15
Q3 = 3 * 4 = 12th term
The 12th term is 6
So that is the 3rd quartile
4(x + 9) + 5x = 9x - 36
=> 4x + 36 + 5x = 9x - 36
=> 9x + 36 = 9x - 36
=> 9x - 9x = -36 - 36
=> 0 = -72
You can see that the equation doesn't hold true.
So there is no solution for this equation.
Answer is C. no real solutions
The choices that are correct when determining the distance between −56 and 69 are |-56 - 69| and 125 units
<h3>How to determine the
choices that are correct when determining the
distance between −56 and 69?</h3>
The endpoints are given as
−56 and 69
The distance between the endpoints is calculated using
Distance = |Difference between endpoints|
So, we have:
Distance = |-56 - 69|
Evaluate
Distance = 125
Hence, the choices that are correct when determining the distance between −56 and 69 are |-56 - 69| and 125 units
Read more about number line at
brainly.com/question/4727909
#SPJ1
Answer:
x^5y^5
Step-by-step explanation:
<em>here's</em><em> your</em><em> solution</em>
=> if base are same then power get added in multiplication
=> so, x^2 * y^4 * x^3 * y^1
=> x^2 * x^3 * y^4 * y^1
=> x^5*y^5
hope it helps
Answer:
centre = (0, 0 ), radius = 5
Step-by-step explanation:
The equation of a circle centred at the origin is
x² + y² = r² ( r is the radius )
x² + y² = 25 ← is in this form
with centre = (0, 0 ) and r = 
= 5
