Answer:
P(Sum of the two dice is 7) = 6/36
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
In this problem, we have that:
A fair dice can have any value between 1 and 6 with equal probability. There are two fair dices, so we have the following possible outcomes.
Possible outcomes
(first rolling, second rolling)
(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)
(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)
(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)
(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)
(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)
(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)
There are 36 possible outcomes.
Desired outcomes
Sum is 7, so
(1,6), (6,1), (5,2), (2,5), (3,4), (4,3).
There are 6 desired outcomes, that is, the number of outcomes in which the sum of the two dice is 7.
Answer
P(Sum of the two dice is 7) = 6/36
