Thank u for posting a picture!
And I believe that it would be vertical because they are the same and they r across from each other and share the same point of S
Hope this helps have a nice day!!
Yes, your answer is correct.
Answer: <span>Postulate 4: If two points lie in a plane, the line containing them lies in that plane.
</span>That is because two points, call them A and B, always form a line, and so, given that they form the line AB and they are in the plane Q, the line AB is in the plane Q.<span />
Answer:
a=-1
Step-by-step explanation:
a(n) = -6+3(n-1)
a(n) = -6+3n-3
a(n) -n=-6+3n-n-3
a=-6+3-3
+3 +3
a3=-3
---- ----
3 3
a=-1
Answer:
- r(0) = <0, 100> . . . . . . . .meters
- r'(0) = <7.071, 7.071> . . . . meters per second
Step-by-step explanation:
<u>Initial Position</u>
The problem statement tells us we're measuring position from the ground at the base of the building where the projectile was launched. The initial horizontal position is presumed to be zero. The initial vertical position is said to be 100 meters from the ground, so (in meters) ...
r(0) = <0, 100>
<u>Initial Velocity</u>
The velocity vector resolves into components in the horizontal direction and the vertical direction. For angle α from the horizontal, the horizontal component of velocity is v₁·cos(α), and the vertical component is v₁·sin(α). For v₁ = 10 m/s and α = π/4, the initial velocity vector (in m/s) is ...
r'(0) = <10·cos(π/4), 10·sin(π/4)>
r'(0) ≈ <7.071, 7.071>
