Answer:
Consecutive odd integers are 19 , 21 & 23
Step-by-step explanation:
Let the first 3 consecutive odd intergers be x , (x + 2) and (x + 4).
According to the question,


Eliminating 2x from both the sides,



So, the consecutive odd integers are = 19 , 21 & 23.
Answer:
Step-by-step explanation:
Hello,

Thanks
Answer:
<em>If statement(1) holds true, it is correct that </em>
<em> is an integer.</em>
<em>If statement(2) holds true, it is not necessarily correct that </em>
<em> is an integer.</em>
<em></em>
Step-by-step explanation:
Given two positive integers
and
.
To check whether
is an integer:
Condition (1):
Every factor of
is also a factor of
.

Let us consider an example:

which is an integer.
Actually, in this situation
is a factor of
.
Condition 2:
Every prime factor of <em>s</em> is also a prime factor of <em>r</em>.
(But the powers of prime factors need not be equal as we are not given the conditions related to powers of prime factors.)
Let


which is not an integer.
So, the answer is:
<em>If statement(1) holds true, it is correct that </em>
<em> is an integer.</em>
<em>If statement(2) holds true, it is not necessarily correct that </em>
<em> is an integer.</em>
<em></em>
Answer: Option 'a' is correct.
Step-by-step explanation:
Since we have given that
"THIS MESSAGE IS TOP SECRET."
We need to use the Caesar cipher.
As in general we always take a shift of 3 keys in Caesar cipher.
so, According to shift of 3 keys it becomes,
T→W
H→K
I→L
S→V
M→P
E→H
A→D
G→J
O→R
C→F
R→U
P→S
So, it can be written as
"THIS MESSAGE IS TOP SECRET."
WKLVP HVVDJ HLVWR SVHFU HW.
we make a set of 5 letters in a word after Caesar cypher.
Hence, Option 'a' is correct.
If there is a negative tile and a positive tile, it creates a zero pair.
Like terms can occur with the same variables (except for terms with exponents)