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Kisachek [45]
2 years ago
14

Index notation simplify 4^9 x 4^3

Mathematics
1 answer:
LenKa [72]2 years ago
7 0

Answer:

4^{12}

Step-by-step explanation:

Using the rule of exponents

a^{m} × a^{n} = a^{(m+n)} , then

4^{9} × 4^{3} = 4^{(9+3)} = 4^{12}

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The volume of this prism
Licemer1 [7]

<em>answer = 66 \:  {cm}^{3}  \\ solution \\ volume = lwh \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  =  \: 11 \times 3 \times 2 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 66 \:  {cm}^{3}  \\ hope \: it \: helps \\ good \: luck \: on \: your \: assignment</em>

5 0
3 years ago
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John has 12 pounds of dog food and is going to separate it into 3/4 pound portions. How many portions of dog food will he have?
NNADVOKAT [17]

16 portions

explanation:

12 / 3/4

   = 12 * 4/3 

= 4*4 = 16

7 0
2 years ago
Please solve this, will rate 5 stars and mark as STAR!​
Nina [5.8K]

Answer:

\boxed{5 \cdot \sqrt{2}  \cdot \sqrt[6]{5} }

Step-by-step explanation:

\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }

\sqrt{\sqrt[3]{10} } \implies (10^\frac{1}{3} )^\frac{1}{2} =10^\frac{1}{6} =\sqrt[6]{10}

\therefore \sqrt{\sqrt[3]{10} }=\sqrt[6]{10}

\text{Solving }\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }

250=2 \cdot 5^3

\sqrt[3]{250}=\sqrt[3]{2\cdot 5^3}=5  \sqrt[3]{2}

Once

\sqrt[6]{2}  \cdot \sqrt[6]{5} = \sqrt[6]{10}

We have

5  \sqrt[3]{2} \cdot \sqrt[6]{2}  \cdot \sqrt[6]{5}

We can proceed considering the common base of exponentials

\sqrt[3]{2}  \cdot \sqrt[6]{2}  =  2^{\frac{1}{3}} \cdot  2^{\frac{1}{6} }  = 2^{\frac{3}{6} } = 2^{\frac{1}{2} }=\sqrt{2}

Therefore,

5  \sqrt[3]{2} \cdot \sqrt[6]{2}  \cdot \sqrt[6]{5} = 5 \cdot \sqrt{2}  \cdot \sqrt[6]{5}

7 0
3 years ago
In triangle QRS, QR = 8 and RS = 5. Which expresses all possible length of side QS?
VLD [36.1K]
Obviously it's answer D) Why?

a) any side of a triangle is SMALLER than the SUM of the 2 others

b) any side of a triangle is GREATER than the DIFFERENCE of the 2 others

Hence D) 8-5 < QS < 8+5==>3 < QS < 13
8 0
3 years ago
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In the rectangle
LekaFEV [45]
In order to form triangle PQT and quadrilateral TQRS, point T must lie on line PS which is 16 cm. long.

If the ratio of PT to TS is 5:3 and the total length of PS is 16, then PT must be 10 and TS must be 6 (10 + 6 =16) and 10:6 is the same ratio as 5:3. Another way to think about it is 5/3 = 10/6.

Now you have all the lengths that you need to find the areas of the quadrilateral and the triangle.

Make sure you draw a diagram of it!!
7 0
2 years ago
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