6x(3x + 1) = 0
First, distribute the 6x to both 3x and 1
6x(3x) = 18x²
6x(1) = 6x
18x² + 6x = 0
To solve, find a number (x) that, when placed in the value of x, will give 0.
0 will be that answer.
18(0)² = 0
6(0) = 0
0 + 0 = 0
0 should be your answer
hope this helps
F(3)= 16. Essentially, you need to substitute 3 for x, which would look like this: 3(3) + 7. Then, by using PEMDAS/the order of operations, multiply 3 by 3 to get 9, and then add 7 to get 16.
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