<h3>
Answer: ds/dt = 11</h3>
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Work Shown:
Before we can use derivatives, we need to find the value of s when (x,y) = (15,20)
s^2 = x^2+y^2
s^2 = 15^2+20^2
s^2 = 225+400
s^2 = 625
s = sqrt(625)
s = 25
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Now we can apply the derivative to both sides to get the following. Don't forget to use the chain rule.
s^2 = x^2 + y^2
d/dt[s^2] = d/dt[x^2 + y^2]
d/dt[s^2] = d/dt[x^2] + d/dt[y^2]
2s*ds/dt = 2x*dx/dt + 2y*dy/dt
2(25)*ds/dt = 2(15)*5 + 2(20)*(10)
50*ds/dt = 150 + 400
50*ds/dt = 550
ds/dt = 550/50
ds/dt = 11
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Side note: The information t = 40 is never used. It's just extra info.
Answer:
<em>Correct answer: C. (1,∞)</em>
Step-by-step explanation:
<u>First Derivative</u>
Given a real continuous function f(x), the first derivative f'(x) represents the slope of the tangent line for any value of x.
If the slope of the line is positive, then the function is increasing, if the slope of the line is negative, the function is decreasing.
The function to analyze is:
Computing the first derivative:
The function will be increasing when:
Dividing by 2:
Solving:
x > 1
This solution is represented by the interval (1,∞)
Correct answer: C. (1,∞)
Answer:
it won't let me download. I'm sorry have a nice day
Answer:
(-2, 0)
Step-by-step explanation:
Use elimination: add the two systems. Because the left is equal to right, you are adding the same thing and it's legal.
-x+3y=2
+ (x+y=-2)
Add each term
-x+x + 3y+y = 2+ -2
4y=0
y=0
x+y=-2
x+0=-2
x=-2
Answer:
the one with pink and white at the top, and the same one with purple and blue on the bottom
Step-by-step explanation: