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lbvjy [14]
3 years ago
12

The common factors of 4p3mn2 and 2pm2n3 is​

Mathematics
1 answer:
pantera1 [17]3 years ago
7 0

Given:

The given terms are

4p^3mn^2 and 2pm^2n^3

To find:

The common factors of given terms.

Solution:

We have,

4p^3mn^2 and 2pm^2n^3

The factor forms are

4p^3mn^2=2\times 2\times p\times p\times p\times m\times n\times n

2pm^2n^3=2\times p\times m\times m\times n\times n\times n

The common factors are 2, p, m, n, n. So,

Common factors = 2\times p\times m\times n\times n

                            = 2pmn^2

Therefore, the common factor of given terms is 2pmn^2.

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KIM [24]

a) x=24b+8v

4 * 24 = 96

120 - 96 = 24

24 / 8 = 3

b) 3

6 * 8 = 48

120 - 48 = 72

72 / 24 = 3

c) 3

120 / 8 = 15

d) 15

120 / 24 = 5

e) 5

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3 years ago
New York City is a popular field trip destination.this year the senior class high school a and high school b planned trips there
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Every bus/van can hold 46 students
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3 years ago
Find the other endpoint of the line segment with the given endpoint (-2, -2) and midpoint (3,10)
34kurt

9514 1404 393

Answer:

  (8, 22)

Step-by-step explanation:

For endpoints A and B, and midpoint M, the relationship of interest is ...

  B = 2M -A

  B = 2(3, 10) -(-2, -2) = (6+2, 20+2)

  B = (8, 22)

The other end point is (8, 22).

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3 years ago
Find the solution set of the inequality: -3x+8 <15
fgiga [73]
I wish I could help u
7 0
3 years ago
Read 2 more answers
Maya wrote the following matrix equation to represent a system of equations:
Ne4ueva [31]
I am somehow confused with the given matrix. Because usually, when the system of equations is given as:

ax + by = c
dx + ey = f

the matrix would be written in this manner:

\left[\begin{array}{ccc}a&b&c\\d&e&f\end{array}\right]

Let me just assume that the arrangement of the given corresponds to this system of equations:

4x + 8y = 0
2x + 5y = 6

So you write it as 

\left[\begin{array}{ccc}4&8&0\\2&5&6\end{array}\right]

In order to solve this, the matrix should look like this where x and y are the answers

\left[\begin{array}{ccc}1&0&x\\0&1&y\end{array}\right]


So, the first thing to do is apply this pattern: Row 2 = Row 1 - 2*Row 2. The result will be

\left[\begin{array}{ccc}4&8&0\\0&-2&-12\end{array}\right]

Next, Row 1 = (Row 1/4) + R2:

\left[\begin{array}{ccc}1&0&-12\\0&-2&-12\end{array}\right]

Lastly, Row 2 = Row 2 / -2:

\left[\begin{array}{ccc}1&0&-12\\0&1&6\end{array}\right]

Thus, the answer is x=-12 and y=6.
7 0
4 years ago
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