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zaharov [31]
3 years ago
7

Problem A park has a large circle painted in the middle of the playground area. The circle is divided into 444 equal sections, a

nd each section is painted a different color. The radius of the circle is 10 \text{ meters}10 meters10, start text, space, m, e, t, e, r, s, end text. What is the area AAA of each section of the circle? Give your answer in terms of pi. A=A=A, equals \text{m}^2m 2 start text, m, end text, squared
Mathematics
2 answers:
Vladimir79 [104]3 years ago
7 0

Answer:

25\pi\ m^2

Step-by-step explanation:

Given that:

A large circle in the park has its middle part painted.

The circle is divided in 4 equal parts.

Radius of the circle = 10 meters

To find:

Area of each section of the circle, A = ?

Solution:

Here, we need to find the area of the bigger circle first and then need to divide it into 4 equal parts to find out the answer.

First of all, let us have a look at the formula for area of a circle with given radius r:

Area = \pi r^2

Here, r = 10 m

Putting the value in the above formula, we get:

So, area = \pi 10^2 = 100\pi\ m^2

Now, there are 4 equal parts of the circle, therefore area of each section will be equal.

Area of each section of the circle:

\dfrac{100\pi}{4} = \bold{25 \pi}\ m^2

schepotkina [342]3 years ago
5 0

Answer:

Its 25pi

Step-by-step explanation:

I got it right on Khan

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Mars2501 [29]
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3 0
3 years ago
You're standing on the ground 7777 meters away from the bottom of a tall tower. The tower itself is 346346 meters tall. What is
lys-0071 [83]

Answer:

88.7°

Step-by-step explanation:

First, visualize. Assuming that the tower is at a perfectly 90° angle to the ground, you have a right triangle. We will call this triangle ΔABC where A is where you are, B is the top of the tower, and C is the base of the tower. Now we know the following:

∠A = ?

∠B = ?

∠C =  90

a = 346346

b = 7777

c = ?

Note: Triangles are labeled with three pairs of letters: a, b and c and A, B and C. The lower case letters, a, b and c represent the sides, and the upper case letters are the angles that are directly opposite of those sides. (see attached reference)

c is easy, c is the hypotenuse, so you can use the following equation to find the hypotenuse:

a² + b² = c²

Rearranged:

c = ± \sqrt{a^{2} +b^{2} }

Substitute a and b:

c = ±\sqrt{346346^{2} +7777^{2} }

Comes out to ~346433.3 meters.

Now if we use the Law of Sines:

\frac{a}{sinA} = \frac{b}{sinB} = \frac{c}{sinC}

We can use c and a, since we're trying to find what angle A is, so the ratio is set up as:

\frac{346346}{sinA} = \frac{346433.3}{sinC}

Well we know that C = 90, and so sin(90) in degrees (as opposed to radians) is 1. So then the set of equations is now:

\frac{346346}{sinA} = \frac{346433.3}{1}

Cross Multiply to get rid of the fractions:

346346 = 346433.3 * sin(A)

Divide:

\frac{346346}{346433.3} = sin(A)

Using a calculator, if you take the arcsin of that fraction, you will get what angle A is supposed to be:

arcsin( \frac{346346}{346433.3} ) = ∠A = 88.7°

5 0
2 years ago
3. A plane travels at a constant speed. It takes 6 hours to travel 3,360 miles. (20 points)
Vilka [71]

Answer:

a. The plane's speed in mph is 560

b. At this rate, the plane can travel 5,600 miles in 10 hours.

Step-by-step explanation:

In order to find the planes speed in mph, some simple arithmetic must be done and you should divide 3,360 by 6.   Now that you have determined that 3,360/6 equals 560, you know that in order to figure out how many miles the plane can travel in 10 hours, all you must do is multiply 560 by 10 which equals 5,600.

7 0
3 years ago
Brainliest available to the correct answer!
Andrew [12]
What is the question? :)
8 0
3 years ago
1. Lenny cleans 75 cars in 5 days. At this rate, how many days will it take him to wash 90 cars? *please I need some help
Ahat [919]
Answer: 6 days

Explanation: If he washes 75 cars in 5 days; and you need to find how many days it takes to wash 90 you do 75 divided by 5 which is 15; so he washes 15 cars in a day, then do 90 divided by 15 which is 6 days
8 0
3 years ago
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