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OverLord2011 [107]

3 years ago

9

The total weight of 25 bags of rice, 23 bags of flour and 19 bags of sugar is 2,719 pounds. Each bag of rice weighs 35 pounds an

d each bag of flour weighs 43 pounds. What is the weight of a bag of sugar, assuming they all weigh the same?

1 answer:

Tems11 [23]3 years ago

4 0

Just do 25 23 then what

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What is the reciprocal of 0.125

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1/0.125
I really hope this helps

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How to solve linear and nonlinear equations graphically?

Ede4ka [16]

Plot the equation. If you wish to solve a polynomial, let y= polynomial and plot the graph. Best set up a table of values first.
Where the graph crosses the x axis there is a solution for x. There are also solutions for other horizontal lines (y values) by looking at intersections of the graph with these lines. This technique works for linear and non linear equations. You can also use graphs to solve 2-variable systems of equations by examining where the graphs intersect one another. The disadvantage is that you may not be able to have sufficient detail for high degrees of accuracy because of the scale of the graph and drawing inaccuracies.

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3 years ago

Stan's, marks, and wayne's ages are consecutive whole numbers. stan is the youngest, and wayne is the oldest. the sum of their a

White raven [17]

Stan's, Mark's and Wayne's ages are 35 , 36 and 37 years respectively.

<em><u>Explanation</u></em>

Stan's, Mark's and Wayne's ages are <u>consecutive whole numbers</u> and Stan is the youngest and Wayne is the oldest.

So, lets assume that Stan's, Mark's and Wayne's ages are $n, n+1$ and $n+2$

Given that, the sum of their ages is 108. So, the equation will be.....

$n+(n+1)+(n+2)=108\\ \\ 3n+3=108\\ \\ 3n=108-3=105\\ \\ n=\frac{105}{3}=35$

So, Stan's age is 35 years , Mark's age is (35+1)= 36 years and Wayne's age is (35+2)= 37 years.

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3 years ago

The ages of armadillos are normally distributed, with a mean of 14 years and a standard deviation of 1.2. Approximately what per

vovangra [49]

Answer:

Percentage of armadillos between 13 and 17 years = 79.052%f using Standard Normal Distribution Tables

Step-by-step explanation:

As we know from normal distribution: z(x) = (x - Mu)/SD

where x = targeted value; Mu = Mean of Normal Distribution; SD = Standard Deviation of Normal Distribution

Therefore using given data: Mu = 14, SD = 1.2 we have z(x) by using z(x) = (x - Mu)/SD as under:

Approach 1 using Standard Normal Distribution Table:

z for x=17: z(17) = (17-14)/1.2 gives us z(17) = 2.5

z for x=13: z(13) = (13-14)/1.2 gives us z(13) = -0.83

Afterwards using Normal Distribution Tables we find the probabilities as under:

P(17) using z(17) = 2.5 gives us P(17) = 99.379%

Similarly we have:

P(13) using z(13) = -0.83 gives us P(13) = 20.327%

Finally in order to find out the probability between 17 & 13 years we have:

Percentage of armadillos between 13 and 17 years = P(17) - P(13) = 99.379% - 20.327% = 79.052%

The standard normal distribution table is being attached for yours easiness.

Approach 2 using Excel or Google Sheets:

P(17) = norm.dist(17,14,1.2,1)

P(13) = norm.dist(13,14,1.2,1)

Percentage of armadillos between 13 and 17 years = { P(17) - P(13) } * 100

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