1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
denpristay [2]
3 years ago
14

A sandbox has a area of 26 square feet and the length is 5 1/2 feet what is the width of the sandbox?

Mathematics
2 answers:
nexus9112 [7]3 years ago
7 0

We can write an equation

26=5.5*x

26 is the area and 5.5 is the length

To get x alone divide26 by 5.5

The answer is 52/11

Ulleksa [173]3 years ago
3 0

Answer:

4.5 ft

Step-by-step explanation:

Area = length times width.  Let A = 26 ft^2 and divide it by L = 5.5 ft, to obtain the width W.  W = 26 ft^2  /  5.5 ft = 4.54 ft, or 4.5 ft to the nearest tenth foot.


You might be interested in
Which expressions are equivalent to the given expression?
gizmo_the_mogwai [7]

Answer: Choice C. \frac{1}{x^{2}y^{5}  }and Choice E. x^{-2} y^{-5}

Step-by-step explanation:

Algebraic exponents.

5 0
3 years ago
Read 2 more answers
Which of the following statements are true of the discriminant? The discriminant is b2 – 4ac in the quadratic formula. The discr
steposvetlana [31]
A is true If im not mistaking 
7 0
3 years ago
Read 2 more answers
If 6 beads weigh 48 grams, how many beads weigh 72 grams?
allochka39001 [22]
Nine.
48 divided by 6 is 8, which means that each bead weighs 8 grams.
72 divided by 8 is nine.
4 0
3 years ago
Read 2 more answers
Whenever there are _____________ in a set of data, the mean is not a good way to describe the data.
Lady bird [3.3K]
The answer is outliers because when you have a larger or smaller set than your sequence suggests the mean will move toward the outlier
3 0
3 years ago
Read 2 more answers
The highest recorded temperature during the month of July for a given year in Death Valley, California has an approximately norm
S_A_V [24]

Answer:

P(X

And we can find this probability using excel or the normal standard tabe and we got:

P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the temperatures of a population, and for this case we know the distribution for X is given by:

X \sim N(123.8,3.1)  

Where \mu=123.8 and \sigma=3.1

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using excel or the normal standard tabe and we got:

P(z

6 0
4 years ago
Other questions:
  • PLEASE ANSWERRRRRRRRRRRRRRRRRRR
    5·1 answer
  • You are baking batches of cookies for a bake sale. Each batch takes 2.5 cups of flour. You have 18 cups of flour. Can you bake 8
    9·1 answer
  • Lin spent 80 minutes doing homework on Monday. Each day from Tuesday
    10·2 answers
  • Question
    9·1 answer
  • Find all the zeros of the polynomial function:<br> y = x3 – 2x² + 9x – 18
    15·1 answer
  • What is 2/3x2/5pls I need an answer fast sorry I suck at math
    15·1 answer
  • The first two terms of an exponential sequence are 18 and 6. What are the next three terms?
    11·1 answer
  • You saved $280 on your new laptop because you bought it online. If this was a 20% savings from the original price, find the orig
    5·1 answer
  • Which expression is equivalent to 5(2n 1)? 2n 1 2n 5 10n 1 10n 5.
    9·1 answer
  • Use the graph to find the following.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!