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juin [17]
3 years ago
11

Based on the figure, which pair of triangles is congruent by the Side Angle Side Postulate?

Mathematics
2 answers:
Ainat [17]3 years ago
7 0
Triangle ABD and Triangle ECD
''''''''''''''''Remember: Vertical angles are congruent '''''''''''''''''''''
So angle ADB and angle CDE are congruent
We know that sides BD and DC are congruent
also sides AD and DE are congruent

:)
Lapatulllka [165]3 years ago
5 0

Answer: Triangle ABC and Triangle ECD


Step-by-step explanation:

In Triangle ABC and Triangle ECD

BD=CD and AD=ED [given in the figure]

∠BDA=∠EDC  [Vertically opposite angles are equal]

⇒ΔABC ≅ ΔECD [By SAS postulate]

SAS postulate or Side Angle Side postulate tells that if two sides and their included angle of one triangle are congruent to two sides and the included angle of another triangle, then the two triangles are congruent.

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Bria took a test with 120 questions. She made an 85%. How many questions did Bria get wrong on the test?
Radda [10]

Answer:

you'd get eighteen questions wrong

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2 years ago
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An air traffic controller is tracking two planes. To start, Plane A is at an altitude of 3427 feet and Plane B is at an altitude
jeyben [28]
3427 + 65.75s = 5000 + 35.5s
65.75s - 35.5s = 5000 - 3427
30.25s = 1573
s = 1573 / 30.25
s = 52 seconds <== they are the same at 52 seconds

3427 + 65.75(52) = 6846
5000 + 35.5(52) = 6846

and their altitude is 6846 <===
6 0
3 years ago
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The height of a ball above the ground in feet is defined by the function h(t) = -16t Squared + 80t +3, where t is the number of
jasenka [17]
Plug in 2 for t.
=> -16*(2^2) +80*2 +3
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6 0
3 years ago
A researcher was interested in seeing how many names a class of 38 students could remember after playing a name game After playi
Andreas93 [3]

Answer:

Proportion of the students recalled more than 15 names is 91.77%.

Step-by-step explanation:

We are given that a researcher was interested in seeing how many names a class of 38 students could remember after playing a name game After playing the name game, the students were asked to recall as many first names of fellow students as possible.

The mean number of names recalled was 19.41 with a standard deviation of 3.17.

<em>Let X = number of names recalled</em>

SO, X ~ N(\mu = 19.41,\sigma^{2} = 3.17^{2})

The z-score probability distribution is given by ;

                  Z = \frac{X-\mu}{\sigma} } } ~ N(0,1)

where, \mu = mean number of names recalled = 19.41

            \sigma = standard deviation = 3.17

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, proportion of the students recalled more than 15 names is given by = P(X > 15 names)

     P(X > 15) = P( \frac{X-\mu}{{\sigma} } } > \frac{15-19.41}{3.17}  } ) = P(Z > -1.39)

                                                      = P(Z < 1.39) = 0.9177  {using z table}

<em>Therefore, proportion of the students recalled more than 15 names is </em><em>91.77%.</em>

4 0
3 years ago
Please help I need help
JulijaS [17]
The rate of change in this pattern is 2:1 comparing the change in 'y' to the change in 'x'.. this means that if you go form 33 to 51 ( an increase of 18), then the the increase from 16 to ? will be 9.  Therefore, ? = 16 + 9 or 25
? = 25
4 0
3 years ago
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