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Llana [10]
3 years ago
14

What are some of the benefits of study groups? Check all that apply. They allow you to do things simultaneously, such as answeri

ng text messages while you study with your friends. They help you feel more engaged with the study material because you are part of a community of learners. They let you attend only when you do not have any conflicts with anything else on your schedule. They give you a way to learn from others by listening to different perspectives on topics. They encourage you to think more deeply about the content through conversations with other group members.
Advanced Placement (AP)
2 answers:
natulia [17]3 years ago
5 0

Answer:

b

d

e

Explanation:

got it correct on edg 2020

Tomtit [17]3 years ago
3 0

Answer:

- They help you feel more engaged with the study material because you are a part of a community of learners.

- They give you a war to learn from others by listening to different perspectives on topics.

- They encourage you to think more deeply about the content through conversations with other group members.

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<span>Bodies have an energy in their interior that is equal to the internal kinetic energy. The internal energy is an extensive quantity that relates to the amount of matter in a given system of particles because it comprises all other forms of energy contained in the atoms of a given substance.</span>
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2. Find the solution of each differential equation. (a) y/2y-8y = 0 (b) 25y/- 20y + 4y = 0 (c) y + 2y + 2y = 0 2. Find the solut
jek_recluse [69]

Each of these ODEs is linear and homogeneous with constant coefficients, so we only need to find the roots to their respective characteristic equations.

(a) The characteristic equation for

y'' - 2y' - 8y = 0

is

r^2 - 2r - 8 = (r - 4) (r + 2) = 0

which arises from the ansatz y = e^{rx}.

The characteristic roots are r=4 and r=-2. Then the general solution is

\boxed{y = C_1 e^{4x} + C_2 e^{-2x}}

where C_1,C_2 are arbitrary constants.

(b) The characteristic equation here is

25r^2 - 20r + 4 = (5r - 2)^2 = 0

with a root at r=\frac25 of multiplicity 2. Then the general solution is

\boxed{y = C_1 e^{2/5\,x} + C_2 x e^{2/5\,x}}

(c) The characteristic equation is

r^2 + 2r + 2 = (r + 1)^2 + 1 = 0

with roots at r = -1 \pm i, where i=\sqrt{-1}. Then the general solution is

y = C_1 e^{(-1+i)x} + C_2 e^{(-1-i)x}

Recall Euler's identity,

e^{ix} = \cos(x) + i \sin(x)

Then we can rewrite the solution as

y = C_1 e^{-x} (\cos(x) + i \sin(x)) + C_2 e^{-x} (\cos(x) - i \sin(x))

or even more simply as

\boxed{y = C_1 e^{-x} \cos(x) + C_2 e^{-x} \sin(x)}

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HELP!! AP Psychology!!
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should be control variable

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Should we notify the physician of the patient's state? Why or why not?
nignag [31]

Answer:

The physician

Explanation:

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