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dalvyx [7]
4 years ago
14

Which of the following represents the zeros of the function

Mathematics
1 answer:
umka21 [38]4 years ago
3 0
<span>g(x) = x^3 - 9x^2 + 2x + 48 ?

Probe some roots. When you use x = - 2

you will have: (-2)^3 - 9(-2)^2 + 2(-2) + 48 = -8 - 36 - 4 + 48 = 0

So, - 2 is a root

From that you can divide x^3 - 9x^2 + 2x + 48 by x + 2 and you will get

x^2 - 11x + 24

Then you can factor that: (x - 8)(x - 3)

So, the three roots are x = - 2, x = 3 and x = 8, which is the option B.

Answer: option B. x = 8, x = -2 , and x = 3
 </span>
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3 0
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Find the quotient of 4/15 ÷ 1/6
Molodets [167]
4/15 = 0.266666....
1/6 = 0.6666666 ....

\frac{4}{15} ÷ \frac{1}{6}  =

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8 0
3 years ago
Which of the following is the correct classification of ∆mnp if m&lt;m=35° and m&lt;p=47°?​
AnnZ [28]

Answer:

D. Obtuse.

Step-by-step explanation:

We are told that in \Delta MNP m\angle M=35^o and m\angle P=47^o. We are asked to classify our given \Delta MNP.

We can see that angle M and angle P are acute angles as their measure is less than 90 degrees.

Let us find the measure of angle P using angle sum property of triangles, which states that sum of interior angles of a triangle is 180 degrees.

So we can set an equation as:

m\angle M+m\angle P+m\angle N=180^o

Upon substituting our given values we will get,

35^o+47^o+m\angle N=180^o

82^o+m\angle N=180^o

82^o-82^o+m\angle N=180^o-82^o

m\angle N=98^o

As measure of angle N is 98 degrees, so angle N is an obtuse angle.

Since a triangle having an angle that measures more than 90 degrees is called an obtuse triangle, therefore, \Delta MNP is an obtuse triangle and option D is the correct choice.

4 0
3 years ago
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F(x)=x^2 what is g(x)
AysviL [449]
Is C g(x) = -X^2 -3

This is the answer
4 0
3 years ago
Fill in the blanks below.
Dmitry_Shevchenko [17]

Answer:

a) <em>Slope of the line m = ∞</em>

<em>b) Slope of the line  m =0</em>

Step-by-step explanation:

<u><em>Explanation:-</em></u>

<u><em>Step(i):-</em></u>

<em>Given points are ( 7,7) and (7,-8)</em>

<em>Slope of the line</em>

<em>                      </em>m = \frac{y_{2} - y_{1} }{x_{2}-x_{1}  }<em />

<em>                     </em>m = \frac{-8-7 }{7-7  } = \frac{-15}{0} = infinite<em />

<em>                   m = ∞</em>

<u><em>Step(ii):-</em></u>

Given points are (-6,7) and (9,7)

<em>Slope of the line</em>

<em>                      </em>m = \frac{y_{2} - y_{1} }{x_{2}-x_{1}  }<em />

<em>                     </em>m = \frac{7-7  }{9-(-6)  } = \frac{0}{15} = 0<em />

<em>Slope of the line  m =0</em>

6 0
3 years ago
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