Equation of line passing through (2, -2) and parallel to 2x+3y = -8 is 
<h3><u>
Solution:</u></h3>
Need to write equation of line parallel to 2x+3y=-8 and passes through the point (2, -2)
Generic slope intercept form of a line is given by y = mx + c
where "m" = slope of the line and "c" is the y - intercept
Let’s first find slope intercept form of 2x+3y=-8 to get slope of line

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c,

We know that slopes of parallel lines are always equal
So the slope of line passing through (2, -2) is also 
Equation of line passing through
and having slope of m is given by


Substituting the values in equation of line we get



Hence equation of line passing through (2 , -2) and parallel to 2x + 3y = -8 is given as 
1.2x + 3.4 = 10.6
subtract 3.4 from each side
1.2x = 7.2
divide each side by 1.2
x = 6
I think it is option 1 sorry if wrong
Answer:
7 800 pour 1/2 heure
Step-by-step explanation:
15 600/2=7 800