<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
4??? fish??? if it's a trick question, then the answer is probably fish :o)
Y = -5x +18
x can be any number, y can be change due to x value
Answer:
No, the absolute value of a number is different from the opposite.
Step-by-step explanation:
For example, the absolute value of 4 is 4.
l4l = 4
But the opposite of 4 is -4.
Absolute value is ALWAYS positive, but the opposite of a positive number is a negative number.
Answer:
416m
Step-by-step explanation:
Volume is found by Length x Width x Height
10.4 x 5 x 8
416
